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The diagonal of a rectangle is 13 cm and one side is 5 cm. Find the area.
Diagonal² = length² + width² 13² = 5² + w² 169 = 25 + w² w² = 144 w = 12 Area = length × width = 5 × 12 = 60 cm²
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Question
Asked 12 days ago|2/23/2026 9:17:17 AM
Updated 12 days ago|2/23/2026 10:03:06 AM
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The diagonal of a rectangle is 13 cm and one side is 5 cm. Find the area.
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cruz30
Diagonal² = length² + width² 13² = 5² + w² 169 = 25 + w² w² = 144 w = 12
Area = length × width = 5 × 12 = 60 cm²
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Added 12 days ago|2/23/2026 10:02:37 AM
This answer has been confirmed as correct and helpful.
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Salas1987
5^2 + b^2 = 13^2.
b^2 = 144.
Area = 5 cm * 12 cm = 60 square cm. The area of the rectangle is 60 square cm.
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Added 12 days ago|2/23/2026 10:03:06 AM
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Questions asked by the same visitor
Estimate the pH of a 0.05 M acetic acid solution (Ka = 1.8 × 10 ).
Weegy:
Given: CH COOH 0.1 M, Ka = 1.8?10 CH COOH H + CH COO Let x = [H ] Ka = x? / (0.1 x) = x? / 0.1 x? = Ka ? 0.1 = 1.8?10 ? 0.1 = 1.8?10 x = (1.8?10 ) = 1.34?10 ? M pH = -log(1.34?10 ?) = 2.87 Answer: pH = 2.87
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Question
Updated 12 days ago|2/23/2026 8:15:08 AM
1 Answer/Comment
3
cruz30
C = 0.05
Ka = 1.8e-5
H_conc = (Ka * C)**0.5
pH = -log10(H_conc)
H_conc = (1.8e-5 * 0.05)**0.5
H_conc= 0.0009487
pH = 3.02
Added 12 days ago|2/23/2026 8:15:08 AM
This answer has been confirmed as correct and helpful.
Calculate the theoretical yield of ethanol from 100 g of glucose via fermentation.
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Question
Not Answered
Updated 12 days ago|2/23/2026 8:12:48 AM
1 Answer/Comment
3
cruz30
mass_glucose = 100 # g
M_glucose = 180.16 # g/mol
M_ethanol = 46.08 # g/mol
moles_glucose = mass_glucose / M_glucose
moles_ethanol = moles_glucose * 2 # C6H12O6 = 2 C2H5OH + 2 CO2
mass_ethanol = moles_ethanol * M_ethanol
moles_glucose = 100 / 180.16
moles_ethanol = moles_glucose * 2
mass_ethanol = 51.1 g
Added 12 days ago|2/23/2026 8:12:48 AM
This answer has been confirmed as correct and helpful.
Determine the amount of oxygen required to completely combust 15 g of propane.
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Question
Not Answered
Updated 12 days ago|2/23/2026 8:12:11 AM
1 Answer/Comment
3
cruz30
mass_C3H8 = 15 # g
M_C3H8 = 44.1 # g/mol
moles_C3H8 = mass_C3H8 / M_C3H8
moles_O2 = moles_C3H8 * 5 # C3H8 + 5 O2 = 3 CO2 + 4 H2O
mass_O2 = moles_O2 * 32
moles_C3H8 = 15 / 44.1
moles_O2 = moles_C3H8 * 5
mass_O2 = 54.2 g
Added 12 days ago|2/23/2026 8:12:11 AM
This answer has been confirmed as correct and helpful.
Calculate the enthalpy change when 2 mol of H reacts with O to form water.
Weegy:
2H2 + O2 2H2O 2 mol H2 + 1 mol O2 - 2 mol H2O
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Question
Updated 12 days ago|2/23/2026 8:14:49 AM
1 Answer/Comment
3
cruz30
n_H2 = 2
H_reaction_per_mol = -286 # kJ/mol H2
H_total = n_H2 * H_reaction_per_mol
H_total = 2 * -286
H_total = -572 kJ
Added 12 days ago|2/23/2026 8:14:39 AM
This answer has been confirmed as correct and helpful.
Estimate the percentage yield if 50 g of NH is produced from 100 g of N and H .
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Question
Not Answered
Updated 12 days ago|2/23/2026 8:11:30 AM
1 Answer/Comment
3
cruz30
mass_NH3_produced = 50
mass_NH3_theoretical = 100
percentage_yield = (mass_NH3_produced / mass_NH3_theoretical) * 100
percentage_yield = (50 / 100) * 100
percentage_yield = 50%
Added 12 days ago|2/23/2026 8:11:30 AM
This answer has been confirmed as correct and helpful.
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