If the equation of a circle is (x - 2)2 (y - 6)2 = 4, it passes through point (5, 6). True or False?
Question
Updated 7/1/2014 8:44:13 PM
Flagged by yeswey [7/1/2014 8:43:10 PM]
Original conversation
User: If the equation of a circle is (x - 2)2 (y - 6)2 = 4, it passes through point (5, 6). True or False?

Question
Updated 7/1/2014 8:44:13 PM
Flagged by yeswey [7/1/2014 8:43:10 PM]
Rating
3
If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, it passes through point (5, 6). FALSE.
When x = 5, y = 6,
(x - 2)^2 + (y - 6)^2 = (5 - 2)^2 + (6 - 6)^2 = 9 + 0 = 9, not 4.
Confirmed by jeifunk [7/1/2014 9:19:03 PM]

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