suppose a 747 jetliner with a mass of 183.75 kg and an initial speed of 26.8m/s is slowed to a stop in 122m.what is the magnitude of the retarding force exerted by the foamcrete on the plane?

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Asked 3/7/2010 2:29:38 PM

Updated 5/31/2023 10:43:25 PM

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Expert answered|toxictoast96|Points 1548|

Question

Asked 3/7/2010 2:29:38 PM

Updated 5/31/2023 10:43:25 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

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To calculate the magnitude of the retarding force exerted by the foamcrete on the plane, we can use the equation:

\(F = \frac{mv^2}{2d}\),

where:

F is the force,

m is the mass of the plane,

v is the initial speed of the plane,

d is the distance over which the plane is slowed down.

Given:

m = 183.75 kg (mass of the plane)

v = 26.8 m/s (initial speed of the plane)

d = 122 m (distance over which the plane is slowed down)

Plugging in these values into the equation, we have:

\(F = \frac{(183.75 kg)(26.8 m/s)^2}{2(122 m)}\).

Calculating this equation, we find:

F 6707.3N

Therefore, the magnitude of the retarding force exerted by the foamcrete on the plane is approximately 6707.3 Newtons.

\(F = \frac{mv^2}{2d}\),

where:

F is the force,

m is the mass of the plane,

v is the initial speed of the plane,

d is the distance over which the plane is slowed down.

Given:

m = 183.75 kg (mass of the plane)

v = 26.8 m/s (initial speed of the plane)

d = 122 m (distance over which the plane is slowed down)

Plugging in these values into the equation, we have:

\(F = \frac{(183.75 kg)(26.8 m/s)^2}{2(122 m)}\).

Calculating this equation, we find:

F 6707.3N

Therefore, the magnitude of the retarding force exerted by the foamcrete on the plane is approximately 6707.3 Newtons.

Added 5/31/2023 10:43:17 PM

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