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Question and answer
Multiply (6xy^2)(3x^3y)
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Question
Asked 11/13/2010 1:04:22 AM
Updated 7/12/2018 8:34:42 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by
alfred123
[7/12/2018 8:34:42 PM]
s
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Multiply (6xy^2)(3x^3y)
Original conversation
User:
Multiply (6xy^2)(3x^3y)
Weegy:
too complicated
Expert answered|lana1924|Points 5|
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Question
Asked 11/13/2010 1:04:22 AM
Updated 7/12/2018 8:34:42 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by
alfred123
[7/12/2018 8:34:42 PM]
New answers
Rating
8
alfred123
M
(6xy^2)(3x^3y) = 18x^4y^3
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Added 7/12/2018 8:34:24 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
8 x 2 + 9 /3
Weegy:
8 x 2 + 9/3 = 16 + 9/3 = 16 + 3 = 19
(More)
Question
Expert Answered
Updated 10/31/2014 6:25:07 PM
0 Answers/Comments
Solve by using PEMDAS: 8 x 2 + 9 /3
Weegy:
8 x 2 + 9 /3 = 16 + 9 /3 = 16 + 3 =19
User:
Solve by using PEMDAS: 6 + 3^2 * 2 / (5 - 2)
Weegy:
6 + 3^2 * 2 / (5 - 2) = 6 + 3^2 * 2 / 3 = 6 + 9 * 2 / 3 = 6 + 18/3 = 6 + 6 = 12
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Question
Expert Answered
Updated 10/31/2014 6:27:07 PM
0 Answers/Comments
Simplify: 3(x + 13)
Weegy:
3x+39
User:
7x + 4 + 3x - 3
Weegy:
10x + 1
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Question
Expert Answered
Updated 6/14/2014 10:37:22 PM
0 Answers/Comments
Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. What must she score on her 4th test so she will have at least an 85 average?
(More)
Question
Updated 1/9/2016 6:54:40 AM
1 Answer/Comment
8
debnjerry
M
Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. To have at least an 85 average, she must score at least 91 on her 4th test.
(75+83+91+x)/4=85
249+x=85*4
249+x=340
x=340-249
x=91
Added 1/9/2016 6:54:40 AM
This answer has been confirmed as correct and helpful.
Solve for x: -2x + 4 >10
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Question
Not Answered
Updated 10/31/2014 6:24:14 PM
1 Answer/Comment
8
andrewpallarca
M
-2x + 4 >10;
-2x > 10 - 4;
-2x > 6;
x < 6/-2;
x < -3
Added 10/31/2014 6:24:14 PM
This answer has been confirmed as correct and helpful.
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