Question and answer
How many terms are in the polynomial abcd + e - fg + h2? one two three four
Question
Asked 3/5/2012 5:07:39 PM
Updated 5/26/2014 1:07:31 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by jerry06 [5/26/2014 1:07:31 PM]
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Original conversation
User: Factor 360t + 10t3 - 120t2.

User: How many terms are in the polynomial abcd + e - fg + h2? one two three four

Weegy: 4
Greenpepper|Points 2902|

User: Divide x4 + 7 by x - 3. x³ - 3x² - 9x - 27 R 88 x³ + 3x² + 9x - 27 R -74 x³ + 3x² + 9x + 27 R 88

User: Factor 9b2 - 4. (3b + 1)(3b - 4) (3b + 2)(3b - 2) (3b - 2)(3b - 2)

Weegy: (a-b)(r+s). please rate this answer,
rebekah_scott|Points 220|

User: Factor 3x2 - 15x - 42. 3(x - 2)(x - 7) 3(x - 2)(x + 7) 3(x - 7)(x + 2)

Weegy: B.3(x - 2)(x + 7). 3 times (x-2) = (3x-6) multiplied by (x + 7) = 3x^2 - 15x-42.
kaichou22|Points 0|

User: Factor 3x2 - 15x - 42.

User: Select the correct difference. -3z7 - (-5z7) 2z7 8z14 -2z7 2z

Question
Asked 3/5/2012 5:07:39 PM
Updated 5/26/2014 1:07:31 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by jerry06 [5/26/2014 1:07:31 PM]
New answers
Rating
3
360t + 10t^3 - 120t^2 = 10t^3 - 120t^2 + 360t = 10t(t^2 - 12t + 36) = 10t(t - 6)^2
Added 5/26/2014 1:02:39 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/26/2014 1:08:57 PM]
3
x^4 + 7 divided by x - 3 is x³ + 3x² + 9x + 27 R 88
Added 5/26/2014 1:03:39 PM
This answer has been confirmed as correct and helpful.
3
9b^2 - 4 = (3b + 2)(3b - 2)
Added 5/26/2014 1:04:28 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/26/2014 1:09:46 PM]
3
3x^2 - 15x - 42 = 3(x^2 - 5x - 14) = 3(x - 7)(x + 2)
Added 5/26/2014 1:06:18 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/26/2014 1:10:06 PM]
3
-3z^7 - (-5z^7) = -3z^7 + 5z^7 = 2z^7
Added 5/26/2014 1:07:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/26/2014 1:10:37 PM]
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(n + 8)(n - 2)
Weegy: 1 - n = 8/11, n = 8/11 + 1, n = 1 8/11 or 19/11 User: Choose the product. a3b2 · 4ab3 4a3b5 4a3b6 4a4b5 (More)
Question
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Updated 2/13/2014 9:18:04 PM
1 Answer/Comment
(n + 8)(n - 2)
= n^2 - 2n + 8n - 16
= n^2 + 6n -16
Added 2/13/2014 9:17:58 PM
This answer has been confirmed as correct and helpful.
Factor k2 + 13k + 12. (k + 2)(k + 6) (k + 3)(k + 4) (k + 12)(k + 1)
Question
Updated 3/30/2014 9:47:10 PM
1 Answer/Comment
k^2 + 13k + 12 = (k + 12)(k + 1)
Added 3/30/2014 9:47:10 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [3/30/2014 9:52:47 PM]
9a4 - b2
Weegy: 9a^4 - b^2 = (3a^2 - b)(3a^2 + b). User: Factor completely. vwx + wxy - xyz x(vw - wy + yz) x(vw - wy - yz) x(vw + wy - yz) (More)
Question
Updated 7/16/2015 6:05:27 AM
1 Answer/Comment
vwx + wxy + xyz
= x(vw + wy + yz)
Added 7/16/2015 6:03:05 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/16/2015 6:05:31 AM]
Find the product. (n + 8)(n - 2) n2 - 6n - 16 n2 + 6n - 16 n2 - 6n + 16
Question
Updated 2/24/2014 3:21:49 PM
1 Answer/Comment
(n + 8)(n - 2)

= n^2 + 6n - 16
Added 2/24/2014 3:21:49 PM
This answer has been confirmed as correct and helpful.
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