The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is

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Asked 6/10/2013 9:55:13 AM

Updated 7/3/2014 8:29:35 PM

2 Answers/Comments

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Flagged by yeswey [7/3/2014 8:28:10 PM]

uxiali|Points 1577|

Question

Asked 6/10/2013 9:55:13 AM

Updated 7/3/2014 8:29:35 PM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [7/3/2014 8:28:10 PM]

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The length of the line segment that joins the points (2, 5) and (9, 8) is sqrt [(9-2)^2+(8-5)^2] = sqrt (49+9) = sqrt 58.

Added 7/3/2014 8:29:19 PM

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Confirmed by yumdrea [7/4/2014 10:16:48 PM]

3

The center of the circle whose equation is (x + 1)² + (y + 2)² = 49 is (-1, -2).

Added 7/3/2014 8:29:35 PM

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Confirmed by yumdrea [7/4/2014 10:16:49 PM]

Find the product of (5a - 7)(2a - 1)?

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Updated 1/28/2018 7:24:33 AM

1 Answer/Comment

(5a - 7)(2a - 1)

= 10a^2 - 5a - 14a + 7

= 10^2 - 19a + 7

= 10a^2 - 5a - 14a + 7

= 10^2 - 19a + 7

Added 1/28/2018 7:24:33 AM

This answer has been confirmed as correct and helpful.

Write the equation of the given circle.
center (-2, -2)
radius of 6
**Weegy:** (x + 2)2 + (y - 4)2 = 49 **User:**
The foci are located at
(6, 0) and (-6, 0)
(0, 6) and (0, -6)
(0, 8) and (0, -8) (More)

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Updated 7/3/2014 8:41:11 PM

1 Answer/Comment

The equation of the circle whose center is at (2, 1) and radius is 3 is
**Weegy:** First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)

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Updated 7/3/2014 8:38:35 PM

1 Answer/Comment

Write the equation of the given circle.
center (3, 3)
radius of 2

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Not Answered

Updated 7/3/2014 8:40:00 PM

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Write the equation of the given circle.
center (1, -5)
radius of 10

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Updated 7/3/2014 8:34:36 PM

1 Answer/Comment

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