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The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is
Question
Asked 6/10/2013 9:55:13 AM
Updated 7/3/2014 8:29:35 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 8:28:10 PM]
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User: The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is

Weegy: the radius is 6
uxiali|Points 1577|

User: Find the length of the line segment that joins the points (2, 5) and (9, 8).

User: Find the length of the line segment that joins the points (2, 5) and (9, 8). v10 v52 v58

User: The center of the circle whose equation is (x + 1)² + (y + 2)² = 49 is

Question
Asked 6/10/2013 9:55:13 AM
Updated 7/3/2014 8:29:35 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 8:28:10 PM]
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The length of the line segment that joins the points (2, 5) and (9, 8) is sqrt [(9-2)^2+(8-5)^2] = sqrt (49+9) = sqrt 58.
Added 7/3/2014 8:29:19 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:16:48 PM]
3
The center of the circle whose equation is (x + 1)² + (y + 2)² = 49 is (-1, -2).
Added 7/3/2014 8:29:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:16:49 PM]
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Questions asked by the same visitor
Find the product of (5a - 7)(2a - 1)?
Question
Expert Answered
Updated 290 days ago|1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 290 days ago|1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Not Answered
Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Expert Answered
Updated 7/3/2014 8:38:35 PM
1 Answer/Comment
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
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Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (1, -5) radius of 10
Question
Not Answered
Updated 7/3/2014 8:34:36 PM
1 Answer/Comment
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
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