x + y = 4
2x + 3y = 0

Question

Asked 4/26/2012 6:37:00 AM

Updated 1/2/2015 2:48:43 PM

1 Answer/Comment

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Flagged by andrewpallarca [1/2/2015 2:48:43 PM]

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Question

Asked 4/26/2012 6:37:00 AM

Updated 1/2/2015 2:48:43 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by andrewpallarca [1/2/2015 2:48:43 PM]

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The solution set for x + y = 4, 2x + 3y = 0 is (x = 12, y = -8).

(x + y = 4) * (-2);

-2x - 2y = -8;

(-2x - 2y = -8) + (2x + 3y = 0);

y = -8;

x - 8 = 4;

x = 4 + 8;

x = 12

(x + y = 4) * (-2);

-2x - 2y = -8;

(-2x - 2y = -8) + (2x + 3y = 0);

y = -8;

x - 8 = 4;

x = 4 + 8;

x = 12

Added 1/2/2015 2:48:42 PM

This answer has been confirmed as correct and helpful.

Solve the system of linear equations below.
x + y = 4
2x + 3y = 0

Question

Updated 12/16/2015 10:52:49 PM

1 Answer/Comment

x + y = 4

2x + 3y = 0

x = -y + 4

2(-y + 4) + 3y = 0

-2y + 8 + 3y = 0

y + 8 = 0

y = -8

x - 8 = 4

x = 4 + 8

x = 12

Solution set: (12, -8)

2x + 3y = 0

x = -y + 4

2(-y + 4) + 3y = 0

-2y + 8 + 3y = 0

y + 8 = 0

y = -8

x - 8 = 4

x = 4 + 8

x = 12

Solution set: (12, -8)

Added 12/16/2015 10:52:49 PM

This answer has been confirmed as correct and helpful.

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