What are the coordinates of the vertex of the graph of the given function? y=-4x^2+3
The coordinates of the vertex of the graph of the given function y=-4x^2+3 is ( 0 , 3 ) when x = 0 , y is the largest when x = 0 , y = -4*0^2 + 3 = 3 so the coordinates of the vertex is ( 0 , 3 ) .
s
Question
Updated 10/29/2014 3:29:06 AM
Edited by andrewpallarca [10/29/2014 3:29:06 AM]
Rating
3
The coordinates of the vertex of the graph of the given function y=-4x^2+3 is ( 0 , 3 )
when x = 0 , y is the largest
when x = 0 , y = -4*0^2 + 3 = 3
so the coordinates of the vertex is ( 0 , 3 ) .
Confirmed by andrewpallarca [10/29/2014 3:29:07 AM], Rated good by andrewpallarca

Questions asked by the same visitor
Solve by factoring. 2x^2-5x=12
Question
Updated 7/25/2014 2:01:54 PM
2x^2 - 5x = 12;
2x^2 - 5x - 12 = 0;
(2x + 3)(x - 4) = 0;
2x + 3 = 0; 2x = -3; x = -3/2;
x - 4 = 0; x = 4

x = -3/2 or x = 4
Solve by factoring. 4a^2-4a=15
Weegy: 4a^2 - 4a = 15; 4a^2 - 4a - 15 = 0; (2a + 3)(2a - 5) = 0; 2a + 3 = 0; 2a = -3; a = -3/2; 2a - 5 = 0; 2a = 5; a = 5/2 a = -3/2 or 5/2 (More)
Question
Updated 7/25/2014 1:51:45 PM
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. d^2-4d-96=0
Weegy: Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. [ d^2-4d-96=0 Answer d? - 4d - 96 = 0 The quadratic formula is ************_______ x = (-b ? ? b? - 4ac)/2a For this equation, a = 1, b = -4, c = -96 ************_________ x = (4 ? ? 16 - ( -384)) / 2 x = (-1 ? 20)/2 x = -8 , 12 ? r? - 35r + 70 = 0 a = 1, b = -35, c = 70 ************_______ x = (-b ? ? b? - 4ac)/2a *************_________ x = (35 ? ? 35? - 4(70))/2 **************___ x = (35 ? 3?105)/2 x ? 2.13 , 32.87 (Both are rounded to the hundredths place) ] User: Identify a, b, and c in the given quadratic equation. 6x^2+77x=13 Weegy: 6x^2+77x=13 quadratic equation(a, b, c) a- 6x^2 b- 77x c- 13 (More)
Question
Updated 10/29/2014 2:59:45 AM
The solution for d^2 - 4 - 96 = 0 is d = 12 ,or d = -8 .
d^2 - 4d - 96 = 0
(d - 2)^2 - 4 - 96 = 0
(d - 2)^2 = 100
d - 2 = 10
d = 12
or
d - 2 = -10
d = -8

Confirmed by sujaysen [10/29/2014 10:12:48 AM]
6x^2 + 77x = 13
6x^2 + 77x - 12 = 0
a = 6 , b = 77 , c = -12

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