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In a survey of 650 students, only 42% ate breakfast every day. Of these, 1/3 always drank orange juice with their breakfast. How many students drank orange juice with their breakfast every day? A. 460 B. 216 C. 126 D. 91
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Question
Asked 6/14/2012 8:41:28 AM
Updated 6/14/2012 9:13:40 AM
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In a survey of 650 students, only 42% ate breakfast every day. Of these, 1/3 always drank orange juice with their breakfast. How many students drank orange juice with their breakfast every day? A. 460 B. 216 C. 126 D. 91
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User:
In a survey of 650 students, only 42% ate breakfast every day. Of these, 1/3 always drank orange juice with their breakfast. How many students drank orange juice with their breakfast every day? A. 460 B. 216 C. 126 D. 91
Weegy:
B. 216
Expert answered|
LoveSolo
|Points 80|
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Question
Asked 6/14/2012 8:41:28 AM
Updated 6/14/2012 9:13:40 AM
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8
debnjerry
650 * .42 * 1/3 = 91
D. 91 students drank orange juice with their breakfast every day.
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Added 6/14/2012 9:13:40 AM
This answer has been confirmed as correct and helpful.
Confirmed by
jeifunk
[1/22/2014 8:06:11 AM]
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Questions asked by the same visitor
The coach of a local basketball team says that her team scored 40 points in the first game and 60 points in the second game. What percent of the first game score is the second game score? A. 110% B. 130% C. 150% D. 170%
Weegy:
The answer is: C. 150% [smile]
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Question
Expert Answered
Asked 6/11/2012 12:57:48 PM
0 Answers/Comments
At a video arcade, the action video games cost $22, which is 110% of last week’s price. What was the price last week? A. $15 B. $18 C. $20 D. $23
Weegy:
C. $20
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Question
Expert Answered
Updated 11/14/2022 2:06:52 PM
1 Answer/Comment
3
MichellDonovan
$22 / 110% = $22 / 1.1 = $20
Added 11/14/2022 2:06:52 PM
This answer has been confirmed as correct and helpful.
The number of students who attended Albany Medical College last year was 1000. This year, attendance has increased to 1350 students. What is this year’s student population compared to last year’s as a percentage? A. 140% B. 135% C. 130% D. 145%
Weegy:
C. 130% is this year?s attendance.
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Question
Expert Answered
Updated 12/18/2024 10:01:38 AM
1 Answer/Comment
3
cruz30
Percentage increase = [(New Value - Old Value) / Old Value] x 100
Percentage increase = [(1350 - 1000) / 1000] x 100
Percentage increase = (350 / 1000) x 100
Percentage increase = 0.35 x 100
Percentage increase = 35%
Therefore, the student population this year is 35% larger than last year.
To express this in terms of the total student population this year compared to last year, we add this percentage to 100%:
Total Percentage = 100% + 35%
Total Percentage = 135%
Therefore, this year's student population compared to last year's is 135%
Added 12/18/2024 10:01:33 AM
This answer has been confirmed as correct and helpful.
The population of a town in Utah in 1997 was 7500. After two years, the population of this town was 115% as much as the population recorded in 1997. What is the population of the town after two years? A. 8425 B. 8500 C. 8625 D. 8750
Weegy:
Than answer is 8500
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Question
Expert Answered
Updated 9/9/2023 12:33:22 PM
1 Answer/Comment
3
MichellDonovan
The towns population was increased by 115%, so we have to get how much 15% of 7500 is.
15% x 7500 = 1125
We then add these two (1125, 7500) to get 8625.
Added 9/9/2023 12:33:22 PM
This answer has been confirmed as correct and helpful.
A jewelry store marked up the price of its most popular necklace. The new price of the necklace is $455, which is 130% of the original price. What was the original price of the necklace? A. $300 B. $350 C. $375 D. $325
Weegy:
D. 325
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Question
Expert Answered
Updated 8/24/2022 11:22:40 AM
1 Answer/Comment
3
MichellDonovan
To solve this, I would write a proportion, it makes everything easier.
Since we don't know what the original value is, it will be x. The second proportion is the percents of everything.
455 130
x 100
Cross multiply 455 by 100 and then divide it by 130.
This gives you 350.
The original Price of the necklace is 350
Added 8/24/2022 11:22:40 AM
This answer has been confirmed as correct and helpful.
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