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Find the product of (5a - 7)(2a - 1)?
(5a - 7)(2a - 1) = 10a^2 - 5a - 14a + 7 = 10^2 - 19a + 7
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Asked 6/10/2013 8:54:47 AM
Updated 170 days ago|1/28/2018 7:24:33 AM
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Edited by Masamune [1/28/2018 7:24:32 AM]
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(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 170 days ago|1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
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The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
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Updated 7/3/2014 8:38:35 PM
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The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Added 7/3/2014 8:38:35 PM
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Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
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Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
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Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (-2, -2) radius of 6
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Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
Write the equation of the given circle. center (1, -5) radius of 10
Question
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Updated 7/3/2014 8:34:36 PM
1 Answer/Comment
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Added 7/3/2014 8:34:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
Identify the following equation as that of a line, a circle, an ellipse, a parabola, or a hyperbola. x + y = 5 line circle ellipse parabola hyperbola User: x + y = 5 line circle ellipse parabola hyperbola
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Expert Answered
Updated 7/3/2014 8:27:35 PM
1 Answer/Comment
x + y = 5 is a line.
Added 7/3/2014 8:27:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/4/2014 5:04:47 PM]
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