Factor 360t + 10t3 - 120t2.
A.10t(t - 6)(t + 6)
B.10t(t - 6)2
C.-10t(t - 6)(t + 6)

Question

Asked 10/9/2012 9:21:39 AM

Updated 5/29/2014 2:42:44 PM

2 Answers/Comments

s

Expert answered|sekar|Points 15|

Question

Asked 10/9/2012 9:21:39 AM

Updated 5/29/2014 2:42:44 PM

2 Answers/Comments

Rating

3

3x^2 - 15x - 42 = 3(x + 2)(x - 7)

Added 5/29/2014 2:41:54 PM

This answer has been confirmed as correct and helpful.

3

360t + 10t^3 - 120t^2 = 10t(t - 6)^2

Added 5/29/2014 2:42:44 PM

This answer has been confirmed as correct and helpful.

t Object]User: The branch of grammar that deals with forms of words is called

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Updated 10/18/2018 3:54:41 PM

1 Answer/Comment

The branch of grammar that deals with forms of words is called morphology.

Added 10/18/2018 3:54:40 PM

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Find the product.
(n + 8)(n - 2)
n2- 6n - 16
n2+ 6n - 16
n2- 6n + 16 **Weegy:** 3x 2 - x - 15x + 5 = x(3x - 1) - 5(3x -1) = (3x ... [ factors are (x + 0.7863) and (x - 2.11963) How do you factor 3x squared minus 3x minus 60? 3x2 - 3x - 60 = 3(x2 - x - 20) = 3 ... [ ] ] (More)

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Updated 7/19/2014 1:37:25 PM

1 Answer/Comment

Simplify m - {n + [p - (m + n - p)]}.
-2m + 2p
2m - 2p
-2m - 2p **Weegy:** B. 2m **User:** Divide x4 + 7 by x - 3.
x³ - 3x² - 9x - 27 R 88
x³ + 3x² + 9x - 27 R -74
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Question

Updated 6/29/2014 11:36:07 PM

1 Answer/Comment

m - {n + [p - (m + n - p)]}

=m-(n-m-n+2p)

=m-(-m+2p)

=2m-2p

=m-(n-m-n+2p)

=m-(-m+2p)

=2m-2p

Added 6/29/2014 11:36:06 PM

This answer has been confirmed as correct and helpful.

Factor the following polynomial completely.
-x2y2 + x4 + 9y2 - 9x2
(x- 3)(x- 3)(x+y)(x-y)
(x+ 3)(x+ 3)(x+y)(x-y)
(x+ 3)(x- 3)(x+y)(x-y) **Weegy:** (-4 + x^2) (x^2 - y^2). Please rate the answer. **User:** Factor the following polynomial completely.
-x2y2 + x4 + 9y2 - 9x2
(x- 3)(x- 3)(x+y)(x-y)
(x+ 3)(x+ 3)(x+y)(x-y)
(x+ 3)(x- 3)(x+y)(x-y) (More)

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Not Answered

Updated 7/10/2014 8:21:48 PM

2 Answers/Comments

-x^2y^2 + x^4 + 9y^2 - 9x^2

= (x + 3)(x - 3)(x + y)(x - y)

= (x + 3)(x - 3)(x + y)(x - y)

Added 7/10/2014 8:21:48 PM

This answer has been confirmed as correct and helpful.

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