find a quadratic equation with roots -1+4i, -1-4i

a quadratic equation with roots -1+4i, -1-4i is x^2 + 2x + 17 = 0 sum of the roots = (-1+4i) + (-1-4i) = -2 product of the roots = (-1+4i)(-1-4i) = (-1)^2-(4i)^2 = 1-16i^2 = 1-16(-1) = 17 The equation is x^2 + 2x + 17 = 0

Question

Asked 11/19/2014 1:54:47 PM

Updated 11/20/2014 1:57:15 AM

1 Answer/Comment

s

Rating

8

a quadratic equation with roots -1+4i, -1-4i is x^2 + 2x + 17 = 0

sum of the roots = (-1+4i) + (-1-4i) = -2

product of the roots = (-1+4i)(-1-4i) = (-1)^2-(4i)^2 = 1-16i^2 = 1-16(-1) = 17

The equation is x^2 + 2x + 17 = 0

sum of the roots = (-1+4i) + (-1-4i) = -2

product of the roots = (-1+4i)(-1-4i) = (-1)^2-(4i)^2 = 1-16i^2 = 1-16(-1) = 17

The equation is x^2 + 2x + 17 = 0

Added 11/20/2014 1:57:15 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/20/2014 2:00:08 AM]

34,465,556

questions answered

S

L

1

1

1

1

1

1

1

1

1

1

1

1

1

1

1

1

1

P

1

L

P

1

Points 808 [Total 6681] Ratings 19 Comments 618 Invitations 0 Offline

There are no comments.