Find the equation of the circle whose center and radius are given. center ( -2, -5), radius = 1

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The equation of the circle whose center and radius are center ( -2, -5), radius = 1 is (x + 2)^2 + (y + 5)^2 = 1

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Asked 6/6/2012 10:37:16 AM

Updated 7/15/2014 9:39:25 AM

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The equation of the circle whose center and radius are center ( -2, -5), radius = 1 is (x + 2)^2 + (y + 5)^2 = 1

Added 7/15/2014 9:39:25 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/15/2014 9:41:48 AM]

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Find the equation of the circle whose center and radius are given. center ( 5, 6), radius = 3

Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)

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Updated 7/15/2014 9:41:50 AM

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yeswey

The equation of the circle with center ( 5, 6), radius = 3 is (x - 5)^2 + (y - 6)^2 = 9.

Added 7/15/2014 9:41:50 AM

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Find the equation of the circle whose center and radius are given. center ( 7, -3), radius = 7

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Updated 7/15/2014 9:40:56 AM

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yeswey

The equation of the circle whose center and radius are center ( 7, -3), radius = 7 is (x - 7)^2 + (y + 3)^2 = 49.

Added 7/15/2014 9:40:56 AM

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Find the equation of the circle whose center and radius are given. center (0, 8), radius = 8

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Updated 7/15/2014 9:40:05 AM

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yeswey

The equation of the circle whose center and radius are center (0, 8), radius = 8 is x^2 + (y - 8)^2 = 64

Added 7/15/2014 9:40:05 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/15/2014 9:40:24 AM]

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