Solve each equation.
7x2 = 49

Question

Asked 6/3/2013 9:38:07 AM

Updated 8/19/2014 1:24:59 AM

5 Answers/Comments

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Flagged by yeswey [8/19/2014 1:21:18 AM]

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Question

Asked 6/3/2013 9:38:07 AM

Updated 8/19/2014 1:24:59 AM

5 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [8/19/2014 1:21:18 AM]

Rating

3

7x^2 = 49

x^2 = 49/7 = 7

x = ± sqrt 7

x^2 = 49/7 = 7

x = ± sqrt 7

Added 8/19/2014 1:21:09 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/19/2014 1:29:06 AM]

3

4 = x^2 - 7

x^2 = 4 + 7 = 11

x = ± sqrt 11

x^2 = 4 + 7 = 11

x = ± sqrt 11

Added 8/19/2014 1:21:55 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/19/2014 1:30:57 AM]

3

16x^2 = 49

x^2 = 49/16

x = ± 7/4

x^2 = 49/16

x = ± 7/4

Added 8/19/2014 1:22:38 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/19/2014 1:32:29 AM]

3

5x^2 + 500 = 844.45

5x^2 = 844.45 - 500 = 344.45

x^2 = 344.45/5 = 68.89

x = ± 8.3

5x^2 = 844.45 - 500 = 344.45

x^2 = 344.45/5 = 68.89

x = ± 8.3

Added 8/19/2014 1:24:23 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/19/2014 1:32:56 AM]

3

The equivalent form of the equation t²+5t-24=0 is (t + 8)(t - 3) = 0

Added 8/19/2014 1:24:59 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/19/2014 1:33:13 AM]

Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite.
x y = 6
x - y = 0
one solution
no solution
infinite **Weegy:** The equivalent of x in equation of -6+3x =-9 is -1. **User:** Which of the following would be the correct form of the equation 10t² - 29t = -10 to be able to solve using the zero product property?
**Weegy:** (2t - 5)(5t - 2) (10t + 5)(t - 2) = 0 **User:** Which of the following would be the correct form of the equation 10t² - 29t = -10 to be able to solve using the zero product property?
**Weegy:** (2t - 5)(5t - 2) (10t + 5)(t - 2) = 0 **User:** Select the term that describes the quadratic portion in this quadratic equation.
7x2 - 12x + 16 = 0
**Weegy:** (x-3)^2 (2 x+1) = 0 , 343/54 - (49 (-11/6 + x))/6 + 2 (-11/6 + x)^3 == 0 [ ] **User:** To solve the equation t² - t = 12 by factoring **Weegy:** z/5 - 3 = 12
z/5 = 15
z = 75 **User:** Solve 2x² - 11x + 5 = 0.
(More)

Question

Updated 6/22/2014 7:57:44 PM

1 Answer/Comment

t² - t = 12

t² - t - 12 = 0

(t - 4)(t + 3) = 0

t - 4 = 0 or t + 3 = 0

t = 4 or t = -3

t² - t - 12 = 0

(t - 4)(t + 3) = 0

t - 4 = 0 or t + 3 = 0

t = 4 or t = -3

Added 6/22/2014 7:57:44 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [6/22/2014 8:00:24 PM]

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