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The coordinates of the vertex for y=2x^2+3x+5 is (-3/4 , 31/8) .
y = 2x^2 + 3x + 5
y = 2(x^2 + 3/2x) + 5
y = 2(x + 3/4)^2 - 9/8 + 5
y = 2(x + 3/4)^2 + 31/8
when x = -3/4 ,y is the smallest
when x = -3/4 , y = 31/8
Added 10/29/2014 2:24:36 AM
This answer has been confirmed as correct and helpful.
