Perform the indicated operation.
(n^4 - 2n^3 - 3n^2 + 7n - 2) ÷ (n - 2)

(n^4 - 2n^3 - 3n^2 + 7n - 2) ÷ (n - 2) = (n^4/n-2) - (2n^3/n-2) - (3n^2/n-2) + (7n/n-2) - (2/n-2) = n^3 - 3n + 1 (for is not equal to 2)

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Asked 7/11/2013 8:43:33 PM

Updated 8/22/2015 7:06:42 AM

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Edited by Andrew. [8/22/2015 7:06:40 AM]

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(n^4 - 2n^3 - 3n^2 + 7n - 2) ÷ (n - 2)

= (n^4/n-2) - (2n^3/n-2) - (3n^2/n-2) + (7n/n-2) - (2/n-2)

= n^3 - 3n + 1 (for is not equal to 2)

= (n^4/n-2) - (2n^3/n-2) - (3n^2/n-2) + (7n/n-2) - (2/n-2)

= n^3 - 3n + 1 (for is not equal to 2)

Added 8/22/2015 7:06:42 AM

This answer has been confirmed as correct and helpful.

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?

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Updated 8/6/2014 8:07:45 PM

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The equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5) is y = -3/2x + 7/2

Added 8/6/2014 8:04:51 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/6/2014 8:07:47 PM]

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