A rectangle length increases 12%, width decreases 8%. Change in area?

Question and answer

New area factor = 1.12 × 0.92 = 1.0304 = 3.04% increase

Question

Asked 12 days ago|2/23/2026 10:42:08 AM

Updated 12 days ago|2/23/2026 11:10:36 AM

2 Answers/Comments

Get an answer

Search for an answer or ask Weegy.

New answers

Rating

cruz30

[Deleted]

Added 12 days ago|2/23/2026 11:10:24 AM

This answer has been added to the Weegy Knowledgebase

Deleted by cruz30 [2/23/2026 11:10:31 AM]

cruz30

New area factor = 1.12 × 0.92 = 1.0304 = 3.04% increase

Added 12 days ago|2/23/2026 11:10:36 AM

This answer has been confirmed as correct and helpful.

Comments

There are no comments.

Add an answer or comment

Questions asked by the same visitor

Estimate the pH of a 0.05 M acetic acid solution (Ka = 1.8 × 10 ).

Weegy: Given: CH COOH 0.1 M, Ka = 1.8?10 CH COOH H + CH COO Let x = [H ] Ka = x? / (0.1 x) = x? / 0.1 x? = Ka ? 0.1 = 1.8?10 ? 0.1 = 1.8?10 x = (1.8?10 ) = 1.34?10 ? M pH = -log(1.34?10 ?) = 2.87 Answer: pH = 2.87 (More)

Question

Updated 12 days ago|2/23/2026 8:15:08 AM

1 Answer/Comment

cruz30

C = 0.05
Ka = 1.8e-5
H_conc = (Ka * C)**0.5
pH = -log10(H_conc)
H_conc = (1.8e-5 * 0.05)**0.5
H_conc= 0.0009487
pH = 3.02

Added 12 days ago|2/23/2026 8:15:08 AM

This answer has been confirmed as correct and helpful.

Calculate the theoretical yield of ethanol from 100 g of glucose via fermentation.

(More)

Question

Not Answered

Updated 12 days ago|2/23/2026 8:12:48 AM

1 Answer/Comment

cruz30

mass_glucose = 100 # g
M_glucose = 180.16 # g/mol
M_ethanol = 46.08 # g/mol
moles_glucose = mass_glucose / M_glucose
moles_ethanol = moles_glucose * 2 # C6H12O6 = 2 C2H5OH + 2 CO2
mass_ethanol = moles_ethanol * M_ethanol
moles_glucose = 100 / 180.16
moles_ethanol = moles_glucose * 2
mass_ethanol = 51.1 g

Added 12 days ago|2/23/2026 8:12:48 AM

This answer has been confirmed as correct and helpful.

Determine the amount of oxygen required to completely combust 15 g of propane.

(More)

Question

Not Answered

Updated 12 days ago|2/23/2026 8:12:11 AM

1 Answer/Comment

cruz30

mass_C3H8 = 15 # g
M_C3H8 = 44.1 # g/mol
moles_C3H8 = mass_C3H8 / M_C3H8
moles_O2 = moles_C3H8 * 5 # C3H8 + 5 O2 = 3 CO2 + 4 H2O
mass_O2 = moles_O2 * 32
moles_C3H8 = 15 / 44.1
moles_O2 = moles_C3H8 * 5
mass_O2 = 54.2 g

Added 12 days ago|2/23/2026 8:12:11 AM

This answer has been confirmed as correct and helpful.

Calculate the enthalpy change when 2 mol of H reacts with O to form water.

Weegy: 2H2 + O2 2H2O 2 mol H2 + 1 mol O2 - 2 mol H2O (More)

Question

Updated 12 days ago|2/23/2026 8:14:49 AM

1 Answer/Comment

cruz30

n_H2 = 2
H_reaction_per_mol = -286 # kJ/mol H2
H_total = n_H2 * H_reaction_per_mol
H_total = 2 * -286
H_total = -572 kJ

Added 12 days ago|2/23/2026 8:14:39 AM

This answer has been confirmed as correct and helpful.

Estimate the percentage yield if 50 g of NH is produced from 100 g of N and H .

(More)

Question

Not Answered

Updated 12 days ago|2/23/2026 8:11:30 AM

1 Answer/Comment

cruz30

mass_NH3_produced = 50
mass_NH3_theoretical = 100
percentage_yield = (mass_NH3_produced / mass_NH3_theoretical) * 100
percentage_yield = (50 / 100) * 100
percentage_yield = 50%

Added 12 days ago|2/23/2026 8:11:30 AM

This answer has been confirmed as correct and helpful.

40,356,876

questions answered