Question and answer
Factor 16p4 - 24p3.
Question
Asked 10/8/2012 12:05:57 PM
Updated 6/13/2014 3:11:19 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/13/2014 3:10:43 PM]
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Original conversation
User: Factor 16p4 - 24p3.

Weegy: First, recognize that this format follows that of a difference of two squares: a^2 - b^2. How would you factor this? (a + b)(a - b). [ (Try it: you get a^2 + ab - ab - b^2 = a^2 - b^2) So, what are the square roots of each of the terms above? sqrt of 16p^4 = 4p^2 and sqrt(625q^4) = 25q^2 So, you get (4p^2 - 25q^2)(4p^2 + 25q^2) You can't stop here, however, because you have another difference of two squares in the first term. The second term is not factorable without including imaginary numbers, so let's leave it as it is. Following the above procedure for 4p^2 - 25q^2, you get sqrt(4p^2) = 2p and sqrt(25q^2) = 5q So, 4p^2 - 25q^2 = (2p - 5q)(2p + 5q) Substituting this back, you get the final answer: 16p^4 - 625q^4 = (2p - 5q)(2p + 5q)(4p^2 + 25q^2) ]
wiwit|Points 688|

User: Factor x4y2 + x3y3

Weegy: monomial
LoveSolo|Points 80|

Question
Asked 10/8/2012 12:05:57 PM
Updated 6/13/2014 3:11:19 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/13/2014 3:10:43 PM]
New answers
Rating
3
16p^4 - 24p^3 = 8p^3(2p - 3)
Added 6/13/2014 3:10:41 PM
This answer has been confirmed as correct and helpful.
3
x^4y^2 + x^3y^3 = x^3y^3(x + y)
Added 6/13/2014 3:11:19 PM
This answer has been confirmed as correct and helpful.
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2 Answers/Comments
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Added 8/12/2014 11:29:47 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/12/2014 11:40:23 PM]
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Added 8/12/2014 11:30:31 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/12/2014 11:40:43 PM]
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