Factor 16p4 - 24p3.
Question
Updated 6/13/2014 3:11:19 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/13/2014 3:10:43 PM]
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Original conversation
User: Factor 16p4 - 24p3.

Weegy: First, recognize that this format follows that of a difference of two squares: a^2 - b^2. How would you factor this? (a + b)(a - b). [ (Try it: you get a^2 + ab - ab - b^2 = a^2 - b^2) So, what are the square roots of each of the terms above? sqrt of 16p^4 = 4p^2 and sqrt(625q^4) = 25q^2 So, you get (4p^2 - 25q^2)(4p^2 + 25q^2) You can't stop here, however, because you have another difference of two squares in the first term. The second term is not factorable without including imaginary numbers, so let's leave it as it is. Following the above procedure for 4p^2 - 25q^2, you get sqrt(4p^2) = 2p and sqrt(25q^2) = 5q So, 4p^2 - 25q^2 = (2p - 5q)(2p + 5q) Substituting this back, you get the final answer: 16p^4 - 625q^4 = (2p - 5q)(2p + 5q)(4p^2 + 25q^2) ]
wiwit|Points 688|

User: Factor x4y2 + x3y3

Weegy: monomial
LoveSolo|Points 80|

Question
Updated 6/13/2014 3:11:19 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/13/2014 3:10:43 PM]
Rating
3
16p^4 - 24p^3 = 8p^3(2p - 3)
3
x^4y^2 + x^3y^3 = x^3y^3(x + y)

Questions asked by the same visitor
Factor 3y2 - 4y.
Weegy: User: Factor -4d3 + 28d2 - 4d. Weegy: -4d3 + 28d2 - 4d. = -4d(d^2-7d+1) User: 24a3b3c3 - 84a4b2c factored equals -12a3b2c(2bc2 + 7a). true or false Weegy: True. 24a3b3c3 - 84a4b2c factored equals -12a3b2c(2bc2 + 7a). User: Factor -3x - 3y - 3z. Weegy: -3x - 3y - 3z = -3(x + y + z) User: Factor 10x3 + 8x2 - 6x. (More)
Question
Updated 8/12/2014 11:43:25 PM
3y^2 - 4y = y(3y - 4)
Confirmed by jeifunk [8/12/2014 11:40:23 PM]
10x^3 + 8x^2 - 6x = 2x(5x^2 + 4x - 3)
Confirmed by jeifunk [8/12/2014 11:40:43 PM]
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