Solve the following quadratic equation: (x + 3)2 = 16.
A. x = -3, -4
B. x = 1
C. x = -1, 7
D. x = 1, -7

(x + 3)^2 = 16 ; (x + 3)(x + 3) = 16 ; x^2 + 3x + 3x + 9 = 16 ; x^2 + 6x + 9 = 16 ; x^2 + 6x + 9 - 16 = 0 ; x^2 + 6x - 7 = 0 ; (x - 1)(x + 7) = 0 ; x - 1 = 0 ; x = 1 ; x + 7 = 0 ; x = -7 ; Solution set: x = 1, -7

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Asked 5/15/2013 12:25:21 PM

Updated 38 days ago|6/8/2018 6:18:25 PM

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(x + 3)^2 = 16 ;

(x + 3)(x + 3) = 16 ;

x^2 + 3x + 3x + 9 = 16 ;

x^2 + 6x + 9 = 16 ;

x^2 + 6x + 9 - 16 = 0 ;

x^2 + 6x - 7 = 0 ;

(x - 1)(x + 7) = 0 ;

x - 1 = 0 ;

x = 1 ;

x + 7 = 0 ;

x = -7 ;

Solution set: x = 1, -7

(x + 3)(x + 3) = 16 ;

x^2 + 3x + 3x + 9 = 16 ;

x^2 + 6x + 9 = 16 ;

x^2 + 6x + 9 - 16 = 0 ;

x^2 + 6x - 7 = 0 ;

(x - 1)(x + 7) = 0 ;

x - 1 = 0 ;

x = 1 ;

x + 7 = 0 ;

x = -7 ;

Solution set: x = 1, -7

Added 38 days ago|6/8/2018 6:18:25 PM

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