7x^2+5x-2
7x^2 + 5x - 2 = (7x - 2)(x + 1)
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Updated 5/20/2015 6:23:35 AM
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7x^2 + 5x - 2 = (7x - 2)(x + 1)

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could help me with a few more like this one please solve for x: ( x- 7 )(5x + 2) = 0 show me the steps please
Weegy: In the equation (x - 7)(5x +2) = 0, x = -2/5, 7. All you need to do is find where x - 7 = 0 and 5x + 2 = 0. x - 7 = 0, x = 7. 5x + 2 = 0, 5x = -2, x = -2/5. User: yes thanks Weegy: Okay, the thing about (x - 7)(5x + 2) = 0 is that it has two pieces connected through multiplication. If one of those pieces is zero, than the whole equation equals zero. So, you need to see where each piece is equal to zero. Let's start with x - 7. [ x - 7 = 0 which, if you solve for x, x = 7. Then you have to find where 5x + 2 is equal to zero. 5x + 2 = 0, subtract 2 from both sides and you'll have 5x = -2. Now divide both sides by 5 and you'll end up with x = -2/5. ] (More)
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