A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e. the altitude of the figure?

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A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e. the altitude of the figure?

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Asked 10/21/2011 4:35:15 PM

Updated 12/1/2014 9:57:23 PM

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Flagged by yeswey [12/1/2014 9:55:07 PM]

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User: A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e. the altitude of the figure?

Weegy: D. 85 square units
Expert answered|Dappordanny|Points 222|

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Question

Asked 10/21/2011 4:35:15 PM

Updated 12/1/2014 9:57:23 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [12/1/2014 9:55:07 PM]

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trapezoid area = 1/2 x (a + b) x h = 1/2 x 180 x h = 8100
h = 8100/90 = 90 feet.
the altitude of the lot is 90 feet.

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Added 12/1/2014 9:57:23 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [12/2/2014 2:50:17 AM]

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Added 12/1/2014 9:53:51 PM

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