What type of conic section is the following equation?
4x2 + 4(y2 - 4) = 0
parabola
circle
hyperbola
ellipse

Question

Asked 9/18/2012 9:15:35 AM

Updated 7/11/2014 9:00:16 AM

1 Answer/Comment

Flagged by yeswey [7/11/2014 8:58:16 AM]

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Question

Asked 9/18/2012 9:15:35 AM

Updated 7/11/2014 9:00:16 AM

1 Answer/Comment

Flagged by yeswey [7/11/2014 8:58:16 AM]

Rating

3

The conic section for the equation 4x^2 + 4(y^2 - 4) = 0 is circle.

4x^2 + 4(y^2 - 4) = 0

4x^2 + 4y^2 - 16 = 0

4x^2 + 4y^2 = 16

x^2 + y^2 = 4 which is the equation for a circle with center (0, 0) and radius 2.

4x^2 + 4(y^2 - 4) = 0

4x^2 + 4y^2 - 16 = 0

4x^2 + 4y^2 = 16

x^2 + y^2 = 4 which is the equation for a circle with center (0, 0) and radius 2.

Added 7/11/2014 9:00:16 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [7/11/2014 9:02:18 AM]

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