Question
Updated 7/17/2014 5:03:32 AM
Flagged by andrewpallarca [7/17/2014 5:03:32 AM]
g
Original conversation

Question
Updated 7/17/2014 5:03:32 AM
Flagged by andrewpallarca [7/17/2014 5:03:32 AM]
Rating
8
6x^2 + 3x - 18 = 0

x = [-b ± v(b² - 4ac)] / 2a;
x = -3 ± v(3^2 - 4(6)(-18))]/2(6);
x = -3 ± v(9 + 432)]/12;
x = -3 ± v(441)/12;
x = (-3 ± 21)/12;
x = (-3 + 21)/12 or x = (-3 - 21)/12;
x = 18/12 or x = -24/12;
x = 3/2 or x = -2

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