Solve the system linear equations 3x + y = 0, 6x + y = 6
3x + y = 0, 6x + y = 6 y = -3x 6x + (-3x) = 6 3x = 6 x = 6/3 x = 2 3(2) + y = 0 6 + y = 0 y = -6 Solution set: (2, -6)
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Updated 11/26/2017 3:33:40 AM
Edited by Masamune [11/26/2017 3:32:21 AM]
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3
3x + y = 0, 6x + y = 6

y = -3x
6x + (-3x) = 6
3x = 6
x = 6/3
x = 2

3(2) + y = 0
6 + y = 0
y = -6

Solution set: (2, -6)

Questions asked by the same visitor
Solve by method of substitution 6a=2-b 6a=6-b
Weegy: 6a=2-b_6a=6-b Since b is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. -b+2=6a_6a=-b+6 Since 2 does not contain the variable to solve for, [ move it to the right-hand side of the equation by subtracting 2 from both sides. -b=-2+6a_6a=-b+6 Move all terms not containing b to the right-hand side of the equation. -b=6a-2_6a=-b+6 Multiply each term in the equation by -1. -b*-1=6a*-1-2*-1_6a=-b+6 Multiply -b by -1 to get b. b=6a*-1-2*-1_6a=-b+6 Simplify the right-hand side of the equation by multiplying out all the terms. b=-6a+2_6a=-b+6 Replace all occurrences of b with the solution found by solving the last equation for b. In this case, the value substituted is -6a+2. b=-6a+2_6a=-(-6a+2)+6 Multiply -1 by each term inside the parentheses. b=-6a+2_6a=6a-2+6 Add 6 to -2 to get 4. b=-6a+2_6a=6a+4 Since 6a contains the variable to solve for, move it to the left-hand side of the equation by subtracting 6a from both sides. b=-6a+2_6a-6a=4 Since 6a and -6a are like terms, add -6a to 6a to get 0. b=-6a+2_0=4 Since 0 is not equal 4, there are no solutions. No Solution ] (More)
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