One side of a triangle is 4 cm longer than the shortest side and 2 cm shorter than the longest side. The perimeter is 38 cm. Find the dimensions of the triangle.
A.
8, 12, 18
B.
C.
9.3, 13.3, 15.3
D.
11, 13, 14

Suppose x is one side of the triangle, with given conditions: Its shortest side is: (x - 4)cm Its longest side is: (x + 2)cm The perimeter is: x + (x - 4) + (x + 2) = 38 Solve the equation we get x = 40/3 = 13.3 cm The shortest side = 40/3 - 4 = 40/3 - 12/3 = 28/3 = 9.3 cm The longest side = 40/3 + 2 = 40/3 + 6/3 = 46/3 = 15.3 cm The dimensions of the triangle is C. 9.3, 13.3, 15.3

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Asked 3/22/2014 11:59:13 AM

Updated 3/24/2014 1:18:01 AM

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Suppose x is one side of the triangle, with given conditions:

Its shortest side is: (x - 4)cm

Its longest side is: (x + 2)cm

The perimeter is: x + (x - 4) + (x + 2) = 38

Solve the equation we get x = 40/3 = 13.3 cm

The shortest side = 40/3 - 4 = 40/3 - 12/3 = 28/3 = 9.3 cm

The longest side = 40/3 + 2 = 40/3 + 6/3 = 46/3 = 15.3 cm

The dimensions of the triangle is C. 9.3, 13.3, 15.3

Its shortest side is: (x - 4)cm

Its longest side is: (x + 2)cm

The perimeter is: x + (x - 4) + (x + 2) = 38

Solve the equation we get x = 40/3 = 13.3 cm

The shortest side = 40/3 - 4 = 40/3 - 12/3 = 28/3 = 9.3 cm

The longest side = 40/3 + 2 = 40/3 + 6/3 = 46/3 = 15.3 cm

The dimensions of the triangle is C. 9.3, 13.3, 15.3

Added 3/24/2014 1:18:01 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [3/24/2014 1:19:26 AM]

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