if the sides of a square are lengthened by 6cm, the area becomes 121cm^2. find the length of a side of the orginal square.

If the original square side is x, x>0
=> when it's lengthened it is x+6
S=x^2
S1 = (x+6)^2 = 121,
=> x^2+12x + 36 = 121,
x^2+ 12x - 75=0,
=> x =-17 and x = 5,
but x>0
Final answer: x = 5

Expert answered|shifa saleheen|Points 8864|

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