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if the sides of a square are lengthened by 6cm, the area becomes 121cm^2. find the length of a side of the orginal square.
If the original square side is x, x>0 => when it's lengthened it is x+6 S=x^2 S1 = (x+6)^2 = 121, => x^2+12x + 36 = 121, x^2+ 12x - 75=0, => x =-17 and x = 5, but x>0 Final answer: x = 5
Expert answered|shifa saleheen|Points 8864|
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Asked 1/22/2012 5:13:03 PM
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