y(y + 4) - y2 = 6 is a quadratic equation true or false
Question
Updated 7/3/2014 7:58:22 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 7:58:22 PM]
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Original conversation
User: y(y + 4) - y2 = 6 is a quadratic equation

User: y(y + 4) - y2 = 6 is a quadratic equation true or false

Weegy: False. y(y 4) - y = 6 is written as: y^5 -y - 6 = 0. A quadratic equation is a second-order polynomial equation in a single variable y and this is not a second order polynomial equation.
befeeter|Points 382|

User: Which of the following points is in the solution set of y < x2 - 2x - 8?

Weegy: 4(x - 1) - 2(x2 + 2x + 3) - 6(x + 9)= -2x2-6x -64 is the answer
uxiali|Points 1587|

User: Which of the following points lies on the circle whose center is at the origin and whose radius is 13

User: Which of the following points lies on the circle whose center is at the origin and whose radius is 13 (-5, 12) (6, -7)

Weegy: The answer is: (-5, 12). [smile]
stickman|Points 6262|

Question
Updated 7/3/2014 7:58:22 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 7:58:22 PM]
Rating
3
y(y + 4) - y^2 = 6 is a quadratic equation. FALSE.
Confirmed by yumdrea [7/4/2014 1:40:28 PM]

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