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A circle has equation x2+y2-8x+2y-1=0 what is the radius of this circle
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Question
Asked 4/6/2009 12:35:29 PM
Updated 7/23/2014 3:15:01 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by
yeswey
[7/23/2014 3:14:52 AM], Edited by
andrewpallarca
[7/23/2014 3:22:57 AM]
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A circle has equation x2+y2-8x+2y-1=0 what is the radius of this circle
Original conversation
User:
A circle has equation x2+y2-8x+2y-1=0 what is the radius of this circle
Weegy:
I don't know!
Expert answered|truchocolate08|Points 110|
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Question
Asked 4/6/2009 12:35:29 PM
Updated 7/23/2014 3:15:01 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by
yeswey
[7/23/2014 3:14:52 AM], Edited by
andrewpallarca
[7/23/2014 3:22:57 AM]
New answers
Rating
8
yeswey
A circle has equation x^2+y^2-8x+2y-1=0, the radius of this circle is 3 sqrt 2.
x^2+y^2-8x+2y-1=0
x^2-8x+16+y^2+2y+1=1+16+1
(x-4)^2+(y+1)^2=18
The center of the circle is (4, -1) and the radius is sqrt 18 = 3 sqrt 2.
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Added 7/23/2014 3:15:01 AM
This answer has been confirmed as correct and helpful.
Confirmed by
andrewpallarca
[7/23/2014 3:23:06 AM]
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a circle has equation x2+y2-8x+2y-1=0 what is the radius of this circle
Weegy:
Weegy will move on to the next Weegy expert.
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Expert Answered
Updated 7/23/2014 3:14:02 AM
1 Answer/Comment
8
yeswey
A circle has equation x^2+y^2-8x+2y-1=0, the radius of this circle is 3 sqrt 2.
x^2+y^2-8x+2y-1=0
x^2-8x+16+y^2+2y+1=1+16+1
(x-4)^2+(y+1)^2=18
The center of the circle is (4, -1) and the radius is sqrt 18 = 3 sqrt 2.
Added 7/23/2014 3:14:02 AM
This answer has been confirmed as correct and helpful.
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