Solve for x: -2(x-4) = -3(x + 8) Here are the options: x = 12 x = 4 x = 0 x = -32
Question|Rated good
Updated 12/26/2014 7:59:18 AM
Edited by andrewpallarca [12/26/2014 7:59:17 AM], Confirmed by andrewpallarca [12/26/2014 7:59:18 AM]
Original conversation
User: Solve for x: -2(x-4) = -3(x + 8) Here are the options: x = 12 x = 4 x = 0 x = -32

Weegy: -2(x - 4) = -3(x + 8); -2x + 8 = -3x - 24; -2x + 3x = -24 - 8; x = -32

User: Here is another problem: Solve by using PEMDAS: 5 x 2 + 6 / 3

Weegy: 5 x 2 + 6 / 3 = 10 + 6 / 3 = 10 + 2 = 12

User: Solve by using PEMDAS: 5 + 2^2 x 3 / (5-2)

User: Multiply: (x + 1) (x^2 + 5x - 2)

Weegy: (x + 1) (x^2 + 5x - 2) = x^3 + 6x^2 + 3x - 2

User: Factor completely: x^2 + 9x + 14

Weegy: x^2 + 9x + 14 = (x + 7)(x + 2)

Question|Rated good
Updated 12/26/2014 7:59:18 AM
Edited by andrewpallarca [12/26/2014 7:59:17 AM], Confirmed by andrewpallarca [12/26/2014 7:59:18 AM]
Rating

Questions asked by the same visitor
Solve for x: x^2 + 11x + 24 = 0
Question
Updated 4/5/2015 7:05:34 AM
x^2 + 11x + 24 = 0

(x + 3)(x + 8) = 0;

x + 3 = 0; x = -3;
x + 8 = 0; x = -8

x = {-3, -8}
Confirmed by Andrew. [4/5/2015 12:53:24 PM]
Working with polynomial: (5x – 3.6) – (4x + 1.2)
Weegy: x-4.8 User: Please show the steps on how you got this answer. Thanks (More)
Question
Updated 7/3/2014 1:57:21 PM
(5x – 3.6) – (4x + 1.2)

= 5x - 3.6 - 4x - 1.2

= 5x - 4x - 3.6 - 1.2

= x - 4.8
Confirmed by yumdrea [7/3/2014 2:07:02 PM]
Simplify: -27x^3yz over 36x^2y^2z
Question
Updated 6/22/2014 2:26:53 AM
-27x^3yz/36x^2y^2z
= [(9x^2yz)(-3x)]/[(9x^2yz)(4y)]
= -3x/4y
Confirmed by jeifunk [6/22/2014 2:41:04 AM]
Working with polynomial: (3x^2 + 3x) + (4x + 4). Please show the steps on how you got your answer. Thanks!
Question
Updated 8/10/2014 5:55:48 PM
(3x^2 + 3x) + (4x + 4)

= 3x^2 + 3x + 4x + 4;

= 3x^2 + 7x + 4
Confirmed by andrewpallarca [8/10/2014 5:57:18 PM]
Evaluate: x^2 + 13x + 15 when x = -3
Question
Updated 10/29/2014 9:25:04 PM
x^2 + 13x + 15 when x = -3

(-3)^2 + 13(-3) + 15

= 9 - 39 + 15;

= -15
Confirmed by yumdrea [10/29/2014 9:30:46 PM]
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