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true or false, Robert Frost is considered to be one of the best poets of the Harlem Renaissance
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Asked 6/8/2013 8:39:33 AM
Updated 1/3/2018 12:53:26 PM
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User: true or false, Robert Frost is considered to be one of the best poets of the Harlem Renaissance

Weegy: Robert Frost is considered to be one of the best poets of the Harlem Renaissance
rachell028|Points 1051|

Question
Asked 6/8/2013 8:39:33 AM
Updated 1/3/2018 12:53:26 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by emdjay23 [1/3/2018 12:53:26 PM]
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Robert Frost is considered to be one of the best poets of the Harlem Renaissance. FALSE.
Added 1/3/2018 12:53:24 PM
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Factoring Trinomials x^2+12x+11
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Not Answered
Updated 7/9/2014 1:06:10 PM
1 Answer/Comment
x^2 + 12x + 11 = (x + 11)(x + 1)
Added 7/9/2014 1:06:07 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/9/2014 1:20:42 PM]
Dividing Polynomials 16x^2-56x+40)÷8
Question
Not Answered
Updated 6/27/2014 7:19:50 AM
1 Answer/Comment
(16x^2-56x+40)÷8 = 2x^2-7x+5
Added 6/27/2014 7:19:50 AM
This answer has been confirmed as correct and helpful.
Factor out the greatest common factor x^3+8x^2+2x+16
Weegy: Start with the given expression %28x%5E3%2B8x%5E2%29%2B%282x%2B16%29 Group like terms x%5E2%28x%2B8%29%2B2%28x%2B8%29 Factor out the GCF x%5E2 out of the first group. [ Factor out the GCF 2 out of the second group %28x%5E2%2B2%29%28x%2B8%29 Since we have the common term x%2B8, we can combine like terms So x%5E3%2B8x%5E2%2B2x%2B16 factors to %28x%5E2%2B2%29%28x%2B8%29 In other words, x%5E3%2B8x%5E2%2B2x%2B16=%28x%5E2%2B2%29%28x%2B8%29 ] (More)
Question
Expert Answered
Updated 6/25/2014 3:27:25 AM
1 Answer/Comment
The greatest common factor of x^3+8x^2+2x+16 is 1.
Added 6/25/2014 3:27:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/1/2014 8:28:36 AM]
divide (x^3+2x^2-3x+2)÷(x+1)
Weegy: (x^3+2x^2-3x+2)÷(x+1) = x^2+x-4 with a remainder of 6. (More)
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Expert Answered
Asked 6/3/2013 11:56:22 AM
0 Answers/Comments
for the polynomial function h(x)= 2x^4-x^3+2x^2-4x-3 evaluate the following h(3)
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Updated 6/9/2014 1:23:54 PM
2 Answers/Comments
h(x)= 2x^4 - x^3 + 2x^2 - 4x - 3, h(3):

h(x)= 2(3)^4 - (3)^3 + 2(3)^2 - 4(3) - 3;

h(x)= 2(81) - 27 + 2(9) - 12 - 3;

h(x)= 162 - 27 + 18 - 15;

h(x)= 135 + 3;

h(x)= 138
Added 6/9/2014 1:23:54 PM
This answer has been confirmed as correct and helpful.
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