Weegy: Well, you can't put the flamingo on the line. So, for part b, you have to make sure that the point they give you is NOT on the line. [ To do this, plug in the point to the equation.
y = -2/3x - 12, (-4,-10)
-10 = -(2/3)(-4) - 12
-10 = -28/3
This isn't a true statement, so the point isn't on the line. So you can place the ornament at that point.
Slope-intercept form of a line is
y = mx + b
Where m is the slope and b is the ... (More)