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What volume of NH3 at STP is produced if 25.0 g of N2 is reacted with an excess of H2 ? N2 +3H2 yield 2NH3 Explain Please ...
N2 + 3 H2 ? 2 NH3 (25.0 g N2) / (28.0134 g N2/mol) x (2/1) x (22.414 L/mol) = 40.0 L NH3 at STP "(25.0 g N2) / (28.0134 g N2/mol)" gives the ...
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User: What volume of NH3 at STP is produced if 25.0 g of N2 is reacted with an excess of H2 ? N2 +3H2 yield 2NH3 Explain Please

Weegy: N2 + 3 H2 ? 2 NH3 (25.0 g N2) / (28.0134 g N2/mol) x (2/1) x (22.414 L/mol) = 40.0 L NH3 at STP "(25.0 g N2) / (28.0134 g N2/mol)" gives the number of moles of N2 reacted. Multiplying by "(2/1)" gives the number of moles of NH3 produced. Multiplying by "22.414 L/mol" converts moles of NH3 to liters of NH3 at STP.

Weegy: ... is required to convert a 25.0 g ice cube at ... yield of V205 if you have an excess of oxygen ... during this reaction N2 + 3 H2 ----> 2NH3 start ...

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