What volume of NH3 at STP is produced if 25.0 g of N2 is reacted with an excess of H2 ? N2 +3H2 yield 2NH3
(See answer below)
N2 + 3 H2 ? 2 NH3
(25.0 g N2) / (28.0134 g N2/mol) x (2/1) x (22.414 L/mol) = 40.0 L NH3 at STP
"(25.0 g N2) / (28.0134 g N2/mol)" gives the number of moles of N2 reacted.
Multiplying by "(2/1)" ...
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