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Use the equation above to answer this question: When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?
The ratio between ethene and carbon dioxide is 1 : 2 This means that one mole of ethene will produce two moles of carbon dioxide Because we have two moles of ethene : moles CO2 produced = 2 x 2 = 4
Expert answered|selymi|Points 6313|
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Asked 9/30/2011 9:03:04 AM
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If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced? Round to the nearest tenth. Don't forget the units.
Weegy: Balanced equation: LiOH + HBr ---> LiBr + H2O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. [ (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer) Hope this ... (More)
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If you start with 20 grams of hydrochloric acid, how many grams of sulfuric acid will be produced? Round to the nearest tenth. Don't forget the units.
Weegy: 2HCl + S2 ---> H2S + Cl2 First, [ balance the equation (I already did it here) Then you convert the 20 grams of HCl into that amount in moles. Then you find out how many moles of sulfuric acid will be produced according to stoichiometry. Then convert the amount of sulfuric acid produced in moles into grams. That's how much will be produced And that's the procedure on how to do it. I didn't do the math for you because you need to ... (More)
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Asked 9/30/2011 9:17:07 AM
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In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane?
Weegy: This page give an information view it, User: In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane? Weegy: The formula for combustion is here you can use is it to solve the equation view this page, (More)
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Asked 9/30/2011 9:24:13 AM
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