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mass in grams of 1.35 mol Fe
75.4 g Fe
Expert answered|theresearcher|Points 1080|
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Asked 8/29/2010 3:19:30 AM
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Given: 90.0 g FeCl3 + 52.0 g H2S ; g (excess) H2S after reaction = ?
Weegy: 90g / 162g x 3 x 34.1 g = 28.4 g H2S 52.0 - 27.4 = 23.6 g H2S (More)
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% comp of SO4 in Na2SO4
Weegy: % comp of SO4 in Na2SO4 = 67.6% (More)
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Asked 8/31/2010 3:25:43 PM
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% comp of SO4 in H2SO4
Weegy: Sulfur trioxide is absorbed into 97-98% H2SO4 to form oleum (H2S2O7), also known as fuming sulfuric acid. The oleum is then diluted with water to form concentrated sulfuric acid. (More)
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Asked 8/31/2010 3:26:31 PM
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% comp of SO4 in epsom salts
Weegy: % comp of SO4 in Na2SO4 = 67.6% User: % comp of SO4 in epsom salts (More)
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Asked 8/31/2010 3:27:46 PM
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% comp of SO4 in H2SO4
Weegy: First what you want to do is find the atomic masses of each element involved in the compound and then add them up to find the total molecular mass. Multiply any weight by the number of the same type of atom that's in the compound. [ Sulfuric acid = H2SO4 Hydrogen = 1.01 × 2 = 2.02 grams Sulfur = 32.1 grams Oxygen = 16.0 × 4 = 64.0 grams ------------------------------------------ Sulfuric acid = 98.1 grams Then we take the mass of sulfur and divide it by the total mass of the compound to reach its percent composition. 32.1 grams ÷ 98.1 grams = .327 = 32.7% sulfur in sulfuric acid ] User: % comp of SO4 in H2SO4 (More)
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Asked 8/31/2010 3:29:58 PM
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