Q: Find the area of a regular hexagon if its perimeter is 60 cm.

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Asked 6/18/2010 2:15:36 PM

Updated 6/19/2010 2:38:35 AM

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Since a hexagon has six sides, each sector can be found as follows;

6s = P

s = P / 6

s = 10 cm

Each sector is an equilateral triangle.

Height of each equilateral triangle equals the length of the line segment from the center of the hexagon to middle of each side.

The bisector of each side is 5 cm from the vertex.

Height of each triangle can be found as follows;

h^2 + 5^2 = 10^2

h^2 + 25 = 100

h^2 = 75

h = 5 sqrt(3)

The area of each equilateral triangle is

At = 1/2 s h

At = 1/2 10 * 5 sqrt(3)

At = 25 sqrt(3) cm^2

Since each hexagon is made up of 6 equilateral triangles, the area of the hexagon Ax is 6 times greater than the area of the triangle At.

Ax = 6 At

Ax = 6 (25 sqrt(3))

Ax = 150 sqrt(3) cm^2

sqrt(3) = 1.73,

--> Ax = 150*1.73 = 259.5 cm^2