Rationalize the denominator of 4 over quantity 5 plus square root of 2?
[20 - 4sqrt(2)]/23 is the answer for the rationalized denominator of 4 over quantity 5 plus square root of 2.
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Updated 8/11/2011 9:28:22 PM
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[20 - 4sqrt(2)]/23 is the answer for the rationalized denominator of 4 over quantity 5 plus square root of 2.
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Cassie and Nicholas each rented a movie from two different stores. Cassie paid \$4 for the video plus \$1.50 for each day it was late. Nicholas spent \$6 for his video plus \$1.00 for each day it was late. If they both spent the same amount of money after the video was returned, how many days after the due date did they keep the video?
Weegy: The answer would be 4 days late. Cassie would pay 4\$ plus \$6 in late fees (4 days @ \$1.50 per day) and Nicholas would pay \$6 plus \$4 in late fees. They would each pay \$10. (More)
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is 5x3 – 18x2 + x – 7 monomial, binomial, trinomial or polynomial?
Weegy: This is NOT a polynomial term... ...because the variable has a negative exponent.It is trinomial (More)
Question
Updated 7/1/2014 1:05:37 PM
5x^3 – 18x^2 + x – 7 is a polynomial. It has 4 terms.
Which of the following is one of the factors of x2 – 13x + 12? Answer x – 1 x – 3 x + 12 x + 1
Weegy: Sorry weegy's equations database hasent been fixxed yet (More)
Question
Updated 8/24/2014 4:18:49 AM
The factors of x2 – 13x + 12 is (x-1)(x-12). So the( x-1) is one of the fator in the choices.
x2-13x+12
=x2-x-12x+12
=(.x-1)(x-12)
Which of the following is one of the factors of x2 – 13x + 12?
Weegy: (1 + -1x)(12 + -1x) (More)
Question
Updated 8/24/2014 1:39:00 PM
The factors of x2 – 13x + 12 is( x-1)(x-12) which is the most simplified
Confirmed by sujaysen [8/24/2014 1:39:02 PM]
factors of x15 – 64
Weegy: x5 – 4 (More)
Question
Updated 8/3/2011 12:23:53 PM
x^15 – 64 is actually not factorable. There's nothing you can pull out of that equation to support both values. You can always check your answers at sites like FreeMathHelp. They have a great factoring calculator there, you'd just need to sign up to get more extensive help.
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