What is the distance between the points (2, 6) and (5, 2)?
A) 3
B) 4
C) 5
D) 6

This question has not been answered. Can you answer it? Please add your answer below ...

Question

Asked 6/3/2010 10:47:38 AM

Updated 6/3/2010 12:13:55 PM

1 Answer/Comment

Rating

There are no new answers.

What is the distance between the points (21, 16) and (9, 11)?
A) 13
B) 12
C) 24
D) 22
**Weegy:** The answer is B. 12 . (More)

Question

Expert Answered

Asked 6/3/2010 10:12:35 AM

0 Answers/Comments

What is the midpoint of a segment whose endpoints are (3, -1) and (-5, -3)?
A) (4, -1)
B) (-1, -2)
C) (2, 1)
D) (-2, 1)
**Weegy:** (3-5)/2 , (-1-3)/2 = (-1,-2) ......The midpoint is (-1,-2) (More)

Question

Expert Answered

Asked 6/3/2010 10:17:13 AM

0 Answers/Comments

What is the midpoint of a segment whose endpoints are (-12, -7) and (8, -11)?
A) (-10, -2)
B) (9, -2)
C) (-2, -9)
D) (2, 10)
**Weegy:** (3-5)/2 , (-1-3)/2 = (-1,-2) ......The midpoint is (-1,-2) (More)

Question

Expert Answered

Asked 6/3/2010 10:44:29 AM

0 Answers/Comments

how do i get to weegy pro **Weegy:** Yes, we are here. What is your question? **User:** What is the distance between the points (2, 6) and (5, 2)?
A) 3
B) 4
C) 5
D) 6
**Weegy:** u will have to pay for weegy pro u know that right (More)

Question

Expert Answered

Asked 6/3/2010 10:49:40 AM

0 Answers/Comments

For a Van de Graaff generator to acquire a charge on its surface what must happen?
A. Positive and negative charges must be exactly equal in proportion to each other and remain so for a period of time.
B. An uncharged object must be placed nearby.
C. The metal surface must stay neutral for as long as possible.
D. Positive and negative charges must be separated inside the device and one type of charge must be carried upwards to the metal sphere.
**Weegy:** A. (More)

Question

Expert Answered

Asked 5/28/2010 7:09:04 AM

0 Answers/Comments

23,071,235 questions answered

Points 0 [Total 0] Ratings 0 Comments 0 Invitations 0 Offline

Points 0 [Total 0] Ratings 0 Comments 0 Invitations 0 Offline

d = Sqrt[(x2-x1)^2 + (y2-y1)^2]

--> d = sqrt[(5-2)^2 + (2-6)^2] = sqrt[3^2 + -4^2] = sqrt(9+16) = sqrt(25)

--> d = 5