What is the distance between the points (2, 6) and (5, 2)?
A) 3
B) 4
C) 5
D) 6

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Asked 6/3/2010 10:47:38 AM

Updated 6/3/2010 12:13:55 PM

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What is the distance between the points (21, 16) and (9, 11)?
A) 13
B) 12
C) 24
D) 22
**Weegy:** The answer is B. 12 . (More)

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Asked 6/3/2010 10:12:35 AM

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What is the midpoint of a segment whose endpoints are (3, -1) and (-5, -3)?
A) (4, -1)
B) (-1, -2)
C) (2, 1)
D) (-2, 1)
**Weegy:** (3-5)/2 , (-1-3)/2 = (-1,-2) ......The midpoint is (-1,-2) (More)

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Asked 6/3/2010 10:17:13 AM

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What is the midpoint of a segment whose endpoints are (-12, -7) and (8, -11)?
A) (-10, -2)
B) (9, -2)
C) (-2, -9)
D) (2, 10)
**Weegy:** (3-5)/2 , (-1-3)/2 = (-1,-2) ......The midpoint is (-1,-2) (More)

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Asked 6/3/2010 10:44:29 AM

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how do i get to weegy pro **Weegy:** Yes, we are here. What is your question? **User:** What is the distance between the points (2, 6) and (5, 2)?
A) 3
B) 4
C) 5
D) 6
**Weegy:** u will have to pay for weegy pro u know that right (More)

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Asked 6/3/2010 10:49:40 AM

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For a Van de Graaff generator to acquire a charge on its surface what must happen?
A. Positive and negative charges must be exactly equal in proportion to each other and remain so for a period of time.
B. An uncharged object must be placed nearby.
C. The metal surface must stay neutral for as long as possible.
D. Positive and negative charges must be separated inside the device and one type of charge must be carried upwards to the metal sphere.
**Weegy:** A. (More)

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Asked 5/28/2010 7:09:04 AM

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18,411,878 questions answered

d = Sqrt[(x2-x1)^2 + (y2-y1)^2]

--> d = sqrt[(5-2)^2 + (2-6)^2] = sqrt[3^2 + -4^2] = sqrt(9+16) = sqrt(25)

--> d = 5