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what is the square root of three? **Weegy:** A square root is the number that is multiplied by itself to get another number. Since two multiplied by two (itself) is four, the square root of four is said to be two. (More)

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Updated 6/18/2010 8:42:10 AM

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The perimeter of a rectangle is 100 feet. The length can be represented by (6x - 2) feet and the width can be represented by (x + 3) feet. What is the value of x? **Weegy:** perimeter of a rectangle, P = 2(l + w)
--> 100 = 2([(6x-2)+(x+3)] = 2(6x-2+x+3)
-->100 = 12x-4+2x+6
--> 100 = 14x+2 --> 14x = 98
--> x = 98/14 = 7 (More)

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Asked 6/18/2010 8:06:19 AM

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How can i find geometry flvs answers? **Weegy:** I don't know what flvs is **User:** how can i find florida virtual school answers for geometry? **Weegy:** I would think that is available only to the teacher. If you are having trouble understanding the questions, you can ask specific questions here, but it is probably better to speak to your teacher. (More)

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how can i find florida virtual school answers for geometry? **Weegy:** search it on google (More)

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Asked 6/18/2010 8:22:31 AM

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Find the area of a regular hexagon if its perimeter is 60 cm.

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Updated 6/19/2010 2:38:35 AM

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Perimeter, P = 60 cm

Since a hexagon has six sides, each sector can be found as follows;

6s = P

s = P / 6

s = 10 cm

Each sector is an equilateral triangle.

Height of each equilateral triangle equals the length of the line segment from the center of the hexagon to middle of each side.

The bisector of each side is 5 cm from the vertex.

Height of each triangle can be found as follows;

h^2 + 5^2 = 10^2

h^2 + 25 = 100

h^2 = 75

h = 5 sqrt(3)

The area of each equilateral triangle is

At = 1/2 s h

At = 1/2 10 * 5 sqrt(3)

At = 25 sqrt(3) cm^2

Since each hexagon is made up of 6 equilateral triangles, the area of the hexagon Ax is 6 times greater than the area of the triangle At.

Ax = 6 At

Ax = 6 (25 sqrt(3))

Ax = 150 sqrt(3) cm^2

sqrt(3) = 1.73,

--> Ax = 150*1.73 = 259.5 cm^2

Since a hexagon has six sides, each sector can be found as follows;

6s = P

s = P / 6

s = 10 cm

Each sector is an equilateral triangle.

Height of each equilateral triangle equals the length of the line segment from the center of the hexagon to middle of each side.

The bisector of each side is 5 cm from the vertex.

Height of each triangle can be found as follows;

h^2 + 5^2 = 10^2

h^2 + 25 = 100

h^2 = 75

h = 5 sqrt(3)

The area of each equilateral triangle is

At = 1/2 s h

At = 1/2 10 * 5 sqrt(3)

At = 25 sqrt(3) cm^2

Since each hexagon is made up of 6 equilateral triangles, the area of the hexagon Ax is 6 times greater than the area of the triangle At.

Ax = 6 At

Ax = 6 (25 sqrt(3))

Ax = 150 sqrt(3) cm^2

sqrt(3) = 1.73,

--> Ax = 150*1.73 = 259.5 cm^2

Added 6/19/2010 2:38:35 AM

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