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If an atom contains 12 protons and 10 neutrons, what's its mass number? A. 22 B. 10 C. 12 D. 2
A. 22 12 +10 = 22 Mass number = Number of protons + Number of neutrons
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User: If an atom contains 12 protons and 10 neutrons, what's its mass number? A. 22 B. 10 C. 12 D. 2





Weegy: A. 22 12 +10 = 22 Mass number = Number of protons + Number of neutrons
Expert answered|vjmeneses01|Points 126|

User: Which object emits the most radiation? A. Ice B. Water C. Dirt D. Fire

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Asked 10/5/2013 11:45:24 PM
Updated 89 days ago|8/3/2014 4:40:14 PM
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Fire emits the most radiation.

Added 89 days ago|8/3/2014 4:40:14 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by selymi [9/1/2014 6:17:34 AM]
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Questions asked by the same visitor
What's the net force acting on an 18-kg object if an acceleration of 3.0 m/s2 is produced? A. 6 N B. 36 N C. 12 N D. 54 N
Question
Not Answered
Updated 9/29/2013 2:00:40 PM
5 Answers/Comments
Answer D.

The Formula used is F = ma where:

F is the net force in N,
m is the mass of an object in kg and
a is its acceleration in m/s2.
Added 9/29/2013 12:42:59 PM
Rated good by whalenutz198st, Rated bad by whalenutz198st, Rated good by whalenutz198st
54 n?
Added 9/29/2013 1:06:38 PM
Yes. 54N is the correct answer.
Added 9/29/2013 1:16:45 PM
This answer has been flagged as incorrect.
Rated good by whalenutz198st, Flagged by andrewpallarca
Thank you.
Added 9/29/2013 1:17:37 PM
erikalui, please make sure that you indicate the complete answer not just the letter. It is also important to show the solutions.
Added 9/29/2013 2:00:40 PM
What's the net force acting on an 18-kg object if an acceleration of 3.0 m/s2 is produced? A. 6 N B. 36 N C. 12 N D. 54 N
Weegy: The net force acting on an 18-kg object if an acceleration of 3.0 m/s2 is: 54 N. (More)
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Asked 9/29/2013 1:11:03 PM
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In a controlled experiment, the factor tested is called the A. dependent variable. B. constant. C. control. D. independent variable.
Weegy: In a controlled experiment, the factor tested is called the independent variable. (More)
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