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equation of the circle with center (4, 0) and r =Square root of 5.
The equation of the circle with center (4, 0) and r =Square root of 5 is (x - 4)^2 + y^2 = 5.
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Asked 7/21/2013 5:03:09 PM
Updated 7/3/2014 2:00:41 AM
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The equation of the circle with center (4, 0) and r =Square root of 5 is (x - 4)^2 + y^2 = 5.
Added 7/3/2014 2:00:41 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [7/3/2014 2:13:05 AM]
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