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Q: A bag contains 6 blue marbles, 10 red marbles and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn? A) 4/25. B)3/20.
C)18/125. D)1/6.
A: A bag contains 6 blue marbles, 10 red marbles and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn? 10/25 * 9/24 = 90/600 = 3/20 The probability that two red marbles are drawn is 3/20
Original conversation
User: A bag contains 6 blue marbles, 10 red marbles and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn? A) 4/25. B)3/20. C)18/125. D)1/6.

Weegy: Total marbles in the bag = 10 Number of red ones = 3 Probability of pulling a red one on the first draw = 3/10 = 0.3 Total marbles remaining after the first draw = 9 Number of green ones = 5 Probability of pulling a green one after a red one [ [ has been withdrawn = 5/9 Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent. ] ]

Question
Updated 1/24/2014 5:19:01 PM
This conversation has been flagged as incorrect.
Flagged by debnjerry [1/24/2014 5:18:14 PM]
Rating
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A bag contains 6 blue marbles, 10 red marbles and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
10/25 * 9/24 = 90/600 = 3/20
The probability that two red marbles are drawn is 3/20

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