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Q: 49t6 - 4k8 factored
A: 49t^6 - 4k^8 = -(2 k^4-7 t^3) (2 k^4+7 t^3)
Original conversation
User: 49t6 - 4k8 factored

Weegy: There is one special case for factoring that you may or may not need, depending upon how your book is structured and how your instructor intends to teach factoring quadratics. I call it "factoring in pairs".
MABOO11|Points 401|

Question
Updated 7/10/2014 6:42:45 AM
This conversation has been flagged as incorrect.
Flagged by jeifunk [7/10/2014 6:42:45 AM]
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49t^6 - 4k^8 = -(2 k^4-7 t^3) (2 k^4+7 t^3)

Questions asked by the same visitor
Simplify 5t + (t - 3) - [(7t + 5) - (8 - 3t)].
Question
Updated 5/20/2014 2:22:45 PM
5t + (t - 3) - [(7t + 5) - (8 - 3t)];

5t + (t - 3) - (10t - 3);

5t - 9t = -4t
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