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(6a + b)2 **Weegy:** 12z + 2b (More)

Question

Updated 124 days ago|6/20/2014 8:39:46 AM

1 Answer/Comment

(6a + b)^2

= (6a + b)(6a + b)

= 36a^2 + 6ab + 6ab + b^2

= 36a^2 + 12ab + b^2

= (6a + b)(6a + b)

= 36a^2 + 6ab + 6ab + b^2

= 36a^2 + 12ab + b^2

Added 124 days ago|6/20/2014 8:39:46 AM

This answer has been confirmed as correct, not copied, and helpful.

Find the quotient. y9 ÷ y3 **Weegy:** = y3 (More)

Question

Updated 99 days ago|7/15/2014 2:56:28 AM

1 Answer/Comment

y^9 ÷ y^3 = y^6

Added 99 days ago|7/15/2014 2:56:28 AM

This answer has been confirmed as correct, not copied, and helpful.

Confirmed by andrewpallarca [7/15/2014 2:59:19 AM]

Evaluate y^5 for y = 1. **Weegy:** HY HOW MAY I HELP YOU **User:** Evaluate y5 for y = 1? **User:** can you evaluate y^5 for y= 1? (More)

Question

Updated 117 days ago|6/27/2014 4:12:52 PM

1 Answer/Comment

Write 5,000,039 in scientific notation. **Weegy:** 5.000039 x 10^6 is 5,000,039 in scientific notation. (More)

Question

Updated 15 days ago|10/7/2014 1:18:49 PM

0 Answers/Comments

If the equation of a circle is (x + 4)2 + (y - 6)2 = 25, its center point is **Weegy:** False.
y(y 4) - y = 6 is written as:
y^5 -y - 6 = 0.
A quadratic equation is a second-order polynomial equation in a single variable y and this is not a second order polynomial equation.
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Question

Updated 110 days ago|7/3/2014 7:48:18 PM

1 Answer/Comment

If the equation of a circle is (x + 4)^2 + (y - 6)^2 = 25, its center point is (-4, 6).

Added 110 days ago|7/3/2014 7:48:18 PM

This answer has been confirmed as correct, not copied, and helpful.

Confirmed by andrewpallarca [7/3/2014 7:51:33 PM]

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