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Q: Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels. If Andrea chose 2 coins randomly without replacing them in her purse, what is the probability that she chose 2 dimes?
Original conversation
User: Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels. If Andrea chose 2 coins randomly without replacing them in her purse, what is the probability that she chose 2 dimes?

User: evaluate the expression. 9!-5!(6!)

Weegy: 276480. (9 !) - ((5 !) * (6 !)) = 276 480.

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Questions asked by the same visitor
5y-1/24=3/8
Weegy: y=1/12 (More)
Question
Updated 5/20/2015 4:57:33 AM
(5y-1)/24=3/8
8(5y-1)=3*24
40y-8=72
40y=72+8=80
y=80/40=2
Confirmed by Andrew. [5/20/2015 6:05:40 AM]
7!-5! evaluate
Question
Updated 3/17/2014 6:15:30 PM
7! - 5! = 4920

7! = 5040; 5! = 120

5040 - 120 = 4920

Confirmed by alfred123 [3/18/2014 5:15:08 AM]
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