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Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels. If Andrea chose 2 coins randomly without replacing them in her purse, what is the probability that she chose 2 dimes?
The answer is: 81/625
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User: Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels. If Andrea chose 2 coins randomly without replacing them in her purse, what is the probability that she chose 2 dimes?

Weegy: The answer is: 81/625
Expert answered|patmarone|Points 4979|

User: evaluate the expression. 9!-5!(6!)

Weegy: 276480. (9 !) - ((5 !) * (6 !)) = 276 480.
Expert answered|eturker|Points 2008|

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Asked 5/23/2012 2:27:14 PM
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A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, what is the probability that two black socks are chosen? A. 10/189 B. 5/42 C. 45/392 D. 25/196 User: A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, what is the probability that two black socks are chosen?
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Question
Expert Answered
Asked 5/22/2012 1:53:06 PM
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A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, what is the probability that two blue socks are drawn?
Weegy: Any choices? User: A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, what is the probability that two blue socks are drawn? Weegy: Any choices? User: A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, what is the probability that two blue socks are drawn? A. 17/42 B. 6/14 C. 81/196 D. 153/392 User: A card is chosen at random from a deck of 52 cards. It is replaced, and a second card is chosen. What is the probability that both cards chosen are clubs? Weegy: Assuming the deck has 52 cards (one of each suit, no jokers), there are 4 aces. 4/52 = 1/13 Since we draw a card twice from the full deck, and these events are independent, [ we multiply the probabilities to get the full result: Probability of drawing 2 aces = 1/13 * 1/13 = 1/169 ] User: A card is chosen at random from a deck of 52 cards. It is replaced, and a second card is chosen. What is the probability that both cards chosen are jacks? Weegy: Assuming the deck has 52 cards (one of each suit, no jokers), there are 4 aces. 4/52 = 1/13 Since we draw a card twice from the full deck, and these events are independent, [ we multiply the probabilities to get the full result: Probability of drawing 2 aces = 1/13 * 1/13 = 1/169 ] User: Dianna has 7 quarters, 3 dimes, and 8 nickels in her purse. She reaches into her purse and randomly grabs two coins. What is the probability that Dianna grabs a dime first and then a nickel? Weegy: There are no options to your question. User: Dianna has 7 quarters, 3 dimes, and 8 nickels in her purse. She reaches into her purse and randomly grabs two coins. What is the probability that Dianna grabs a dime first and then a nickel? A. 4/17 B. 2/27 C. 4/51 D. 11/18 Weegy: What is the probability that Dianna grabs a dime first and then a nickel? ... (More)
Question
Expert Answered
Asked 5/22/2012 1:40:46 PM
0 Answers/Comments
7!-5! evaluate
Question
Not Answered
Updated 3/17/2014 6:15:30 PM
1 Answer/Comment
7! - 5! = 4920

7! = 5040; 5! = 120

5040 - 120 = 4920

Added 3/17/2014 6:15:30 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by alfred123 [3/18/2014 5:15:08 AM]
5y-1/24=3/8
Weegy: y=1/12 (More)
Question
Updated 261 days ago|5/20/2015 4:57:33 AM
1 Answer/Comment
(5y-1)/24=3/8
8(5y-1)=3*24
40y-8=72
40y=72+8=80
y=80/40=2
Added 261 days ago|5/20/2015 4:57:30 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by Andrew. [5/20/2015 6:05:40 AM]
enter only the value of the variable. 5y-1/24=3/8
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Question
Expert Answered
Asked 5/23/2012 2:00:29 PM
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