How to find mass/mass percent? How do you find the mass/mass percent given the molarity and density ?
3.00 M NaOH (d = 1.12 g/mL)
(See answer below)
3 M NaOH = 3*40 g/ L = 120 g/ L
and the mass of 1 L is 1120 g
so 120g are 120*100/1120 % = 10.71 % (m/m)
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