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Q: multiply (2x^2+4x+16) (3x-4)
A: (2x^2 + 4x + 16) (3x - 4) = 6x^3 - 8x^2 + 12x^2 - 16x + 48x - 64; = 6x^3 + 4x^2 + 32x - 64
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User: multiply (2x^2+4x+16) (3x-4)

Weegy:
Expert answered|Heather71|Points 1265|

Question
Asked 10/7/2009 5:43:02 PM
Updated 9/2/2014 7:53:07 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by alfred123 [9/2/2014 7:53:04 PM]
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(2x^2 + 4x + 16) (3x - 4)

= 6x^3 - 8x^2 + 12x^2 - 16x + 48x - 64;

= 6x^3 + 4x^2 + 32x - 64
Added 9/2/2014 7:53:07 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/2/2014 8:25:53 PM]
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