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Q: what are the solutions of the system? solv bgraphing y=x^2-2x-1 and y=-2 a.the solution of the system is (-1,-2) b.the system has no solution c.the solution of the system is (-1,2
A: The solution for y=x^2-2x-1 and y=-2 is (1, -2). Analysis: When y = -2, x^2-2x-1 = -2 x^2-2x + 1 = 0 (x - 1)^2 = 0 x = 1 Therefore, the solution is (1, -2)
Question
Updated 3/20/2014 1:10:04 AM
Rating
3
The solution for y=x^2-2x-1 and y=-2 is (1, -2).
Analysis:
When y = -2,
x^2-2x-1 = -2
x^2-2x + 1 = 0
(x - 1)^2 = 0
x = 1
Therefore, the solution is (1, -2)
Confirmed by jeifunk [3/20/2014 1:14:32 AM]

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