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Factor: x2 – 121
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User: Factor: x2 – 121

Weegy: x ? - 1 = (x - 1) (x + 1) Check (x - 1) (x + 1) x (x + 1) - 1 (x + 1) x ? + x - x - 1 x ? - 1
wedekind|Points 1182|

User: 1. Simplify: cd2 + 6a2c2 - 8cd2 + a2c2

Weegy: 7a2c2-7cd2
ASVNBKW88|Points 21|

Question
Asked 7/9/2012 2:59:17 PM
Updated 284 days ago|7/14/2014 8:20:59 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jerry06 [7/14/2014 8:20:59 PM]
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x^2 - 121 = (x - 11)(x + 11)
Added 284 days ago|7/14/2014 8:20:57 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by andrewpallarca [7/16/2014 10:38:29 AM]
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Multiply. (8x4)(6x3)(-5x6)
Weegy: The answer is -12960 User: Multiply. -9x4(5x - 2) Weegy: If 5x - 3 User: Multiply. (9m + 10)2 Weegy: Can you kindly clarify your question please , is Multiply. (9m + 10) x 2 or Multiply. (9m + 10)^2 ? (More)
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Updated 321 days ago|6/8/2014 3:49:40 PM
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(8x^4)(6x^3)(-5x^6) = -240x^13
Added 321 days ago|6/8/2014 3:48:01 PM
This answer has been confirmed as correct, not copied, and helpful.
-9x^4(5x - 2) = -45x^5 + 18x^4
Added 321 days ago|6/8/2014 3:48:41 PM
This answer has been confirmed as correct, not copied, and helpful.
(9m + 10)^2

= (9m + 10)(9m + 10)

= 81m^2 + 90m + 90m + 100

= 81m^2 + 180m + 100
Added 321 days ago|6/8/2014 3:49:40 PM
This answer has been confirmed as correct, not copied, and helpful.
Multiply. (9m + 10)2
Weegy: 38m (More)
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Asked 7/7/2012 4:30:26 PM
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Multiply. (x+1/7)(x-1/7) User: Divide. 6x^4-9x^3-7x^2/x^2
Weegy: So if you take x^2 as a common from the numerator you get x^2(6x^2-9x-7)/x^2 you can cancel the x^2 from numerator and denominator, and the result is just the numerator 6x^2-9x-7 (More)
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Asked 7/7/2012 4:35:30 PM
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Simplify. (63a)3
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Asked 7/7/2012 4:24:45 PM
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Multiply. (x + 2)(x - 4) x represents something
Weegy: Sequence of development would be the order in which the development happens and the rate of development is the speed at which development happens. The difference is important because speed does not necessarily have to do with the sequence. User: I dont understand that. can you multiply this? Weegy: Your question is not displayed in my screen may i know what you dont understand? User: what is (x+2) Multiplied by (x-4) Weegy: x=-4 User: Multiply (9m + 10)*2 Weegy: 38m User: Multiply. -9x4*(5x - 2) Weegy: If 5x - 3 User: Multiply (8x4)*(6x3)*(-5x6) Weegy: The answer is -12960 User: Simplify (63a)3 Weegy: Can you kindly clarify your question please , is it Simplify. (63a) x 3 or , Simplify. (63a)^3 ? User: its times 3 Weegy: = 6 User: Evaluate. (-9)*0 Weegy: The answer is 1. Anything to the power of 0 will equal 1. Try it on your calculator. User: Subtract. (3x3 + 2x5 - 1 + 7x4) - (5 + 9x4 + 9x5 - 5x3) Weegy: 11x5 + 16x4 - 2x3 ? 6 User: Add. (-5 + 6x7 + 2x5) + (9x7 + 5x5 + 9) Weegy: 5x5= 25 User: Evaluate the polynomial. x2 + 3y2 + 2xy, when x = 4 and y = 2 Weegy: Please clarify your question (More)
Question
Expert Answered
Updated 362 days ago|4/27/2014 10:50:06 PM
9 Answers/Comments
(63a)*3 = 189a
Added 362 days ago|4/27/2014 10:43:27 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [4/27/2014 10:46:09 PM]
(-9)*0 = 0
Added 362 days ago|4/27/2014 10:44:05 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [4/27/2014 10:46:10 PM]
(3x^3 + 2x^5 - 1 + 7x^4) - (5 + 9x^4 + 9x^5 - 5x^3)
= 3x^3 + 2x^5 - 1 + 7x^4 - 5 - 9x^4 - 9x^5 + 5x^3
= 8x^3 - 2x^4 - 7x^5 - 6
Added 362 days ago|4/27/2014 10:45:57 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [4/27/2014 10:46:11 PM]
(-5 + 6x^7 + 2x^5) + (9x^7 + 5x^5 + 9)
= -5 + 6x^7 + 2x^5 + 9x^7 + 5x^5 + 9
= 4 + 15x^7 + 7x^5
Added 362 days ago|4/27/2014 10:47:31 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [4/27/2014 10:48:45 PM]
when x = 4 and y = 2,
x^2 + 3y^2 + 2xy
= 4^2 + 3(2^2) + 2(4)(2)
= 16 + 12 + 16
= 28 + 16
= 44
Added 362 days ago|4/27/2014 10:50:06 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by yumdrea [4/27/2014 10:55:47 PM]
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