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Q: Find the midpoint of the segment with the following endpoints O(-6,2), P(0,8) ((-3,3) (3,5) (-3,5) not given
A: (-6+0)/2, (2+8)/2 coordinates: (-3, 5)
Original conversation
User: Find the midpoint of the segment with the following endpoints O(-6,2), P(0,8) ((-3,3) (3,5) (-3,5) not given

Weegy: (-6+0)/2, (2+8)/2 coordinates: (-3, 5)

User: Find the midpoint of the segment with endpoints M(3,5), N(7,1) (-2,2) (5,3) (2,6) not given

Question|Rated good
Updated 10/26/2014 5:47:23 PM
Rating
3
The midpoint of the segment with endpoints M(3, 5), N(7, 1) is: (5, 3).

Midpoint =[(x2 + x1)/2], [(y2 + y1)/2]

= (7 + 3)/2, (1 + 5)/2;

= (10/2), (6/2);

= (5, 3)
Confirmed by andrewpallarca [10/26/2014 5:48:24 PM]

Questions asked by the same visitor
Solve: 3(r + 22) = 4(r + 12) + 10 r = 8 r = -36 r = -8 r = 36
Weegy: 3(r + 22) = 4(r + 12) + 10; 3r + 66 = 4r + 48 + 10; 3r + 66 = 4r + 58; 3r - 4r = 58 - 66; -r = -8; r = 8 User: Solve: 12 (a - 1) = 4 (9 + a) a = 4 a = -2 a = -6 not given (More)
Question
Updated 10/26/2014 5:51:18 PM
12(a - 1) = 4(9 + a)

12a - 12 = 36 + 4a;

12a - 4a 36 + 12;

8a = 48;

a = 48/8;

a = 6 (NOT GIVEN)
Confirmed by andrewpallarca [10/26/2014 5:49:02 PM]
3(r + 22) = 4(r + 12) + 10

3r + 66 = 4r + 58

3r + 66 = 58 - 4r

-r + 66 = 58

-r = 58 - 66

-r = -8

r = -8/1

r = 8
Deleted by jeifunk [10/26/2014 5:51:33 PM], Undeleted by jeifunk [10/26/2014 5:51:37 PM]
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