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will you still come today? Please, is this correct?
yes, it's correct
Expert answered|selymi|Points 2997|
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Asked 5/25/2011 3:18:32 AM
Updated 5/25/2011 4:10:22 AM
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thanks weegy. I want you to solve this mathematics problem for me.
Added 5/25/2011 4:10:22 AM
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if 9 power 1-x is equll to 27 power y. And x-y is equll to minus one whole number one over two. Find the value of x plus y.
Weegy: If 9^(1-x) = 27^y (More)
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Updated 5/22/2011 10:17:38 PM
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I am so sorry for this. Unfortunately, Experts can't hit the enter button or it sends the answer automatically and even more unfortunate is that the conversation closed before I could help you.

Let's do this problem now.

9^(1-x) = 27^y
x - y = -1 1/2... however, I'm going to write this as -3/2 because mixed fractions are just messy.
x - y = -3/2

So let's solve this son of a fun math problem...

We first need to take the log of both sides to bring the exponents down:

log( 9^(1-x) ) = log( 27^y)
(1 - x)*log(9) = y*log(27)

Now get y alone by dividing by log(27):

(1 - x)*log(9)/log(27) = y
log(9)/log(27) = 2/3

(1 - x)(2/3) = y
-(2/3)x + (2/3) = y

Now let's solve for x:
x - y = -3/2
y = x + 3/2

-(2/3)x + (2/3) = x + (3/2)
-(5/3)x = 5/6
x = -1/2

This means we can find y:
y = -1/2 + 3/2
y = 1

So if x = -1/2 and y = 1... x + y = -1/2 + 1 = 1/2

x + y = 1/2

And just to check if x and y are correct, plug back into the original:

9^(1 - x) = 27^y
9^(1-(-1/2)) = 27^1
9^(1 + 1/2) = 27
9^(3/2) = 27
3^(3) = 27
27 = 27

Phew, and for a minute there I thought we were going to have TOO much fun (:
Added 5/22/2011 10:17:38 PM
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